model 2 hiking & discounting Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 4 EXERCISES

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The following question based on discount topic of quantitative aptitude

Questions : The marked price of an article is Rs.500. A shopkeeper gives a discount of 5% and still makes a profit of 25%. The cost price of the article is.

(a) Rs.380

(b) Rs.376

(c) Rs.300

(d) Rs.384

The correct answers to the above question in:

Answer: (a)

Cost price of the article = Rs.x

$x × 125/100 = {500 × 95}/100$

$x = {500 × 95}/125$ = Rs.380

Using Rule 6,

Here, R = 25%, D = 5%, M.P. = Rs.500, C.P. = ?

$\text"M.P."/\text"C.P."= {100 + r}/{100 - D}$

$500/\text"C.P."= {100 + 25}/{100 - 5}$

C.P. = ${500 × 95}/125$ = Rs.38

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Read more based on hiking and discounting Based Quantitative Aptitude Questions and Answers

Question : 1

A shopkeeper marks his goods at 30% above the cost price but allows a discount of 10% at the time of sale. His gain is

a) 20%

b) 17%

c) 18%

d) 21%

Answer: (b)

Let the CP of the article be 100.

According to the question,

The marked price = Rs.130

Discount = 10%

SP = 90% of 130

= ${130 × 90}/100$ = Rs.117

Gain = 117 - 100 = Rs.17

Gain per cent = 17%

since the CP = Rs.100

Using Rule 8,

Here, r = 30%, $r_1$ = 10%

gain % = ${r × (100 - r_1)}/100 - r_1$

= ${30 × (100 - 10)}/100 - 10$

= ${30 × 90}/100 - 10$ = 17%

Question : 2

A merchant purchases a wrist watch for Rs.450 and fixes its list price in such a way that after allowing a discount of 10%, he earns a profit of 20%. Find the list price of the watch.

a) Rs.450

b) Rs.540

c) Rs.600

d) Rs.480

Answer: (c)

Let marked price of the wrist watch be x

${90x}/100 = {450 × 120}/100$

90x = 450 × 120

$x = {450 × 120}/90$ = Rs.600

Using Rule 8,

Here, $r_1$ = 10%, profit = 20%, r = ?

Gain % = ${r × (100 - r_1)}/100 - r_1$

20 = ${r × (100 - 10)}/100 - 10$

20 = ${9r}/10 - 10$

30 = ${9r}/10$

$r = 300/9$%

List price =450 + 450 × $300/9$%

= 450 + 450 × $300/900$

= 450 + 150 = Rs.600

Question : 3

To gain 8% after allowing a discount of 10%, by what per cent cost price should be hiked in the list price ?

a) 11%

b) 20%

c) 18%

d) 9%

Answer: (b)

Let the cost price be Rs.100

and marked price be x.

${x × 90}/100 = 108$

${9x}/10 = 108$

$x = {108 × 10}/9 = 120$

Required Percent = 20%

Using Rule 8,

Here, Gain % = 8%, $r_1$ = 10%, r = ?

Gain % = ${r × (100 - r_1)}/100 - r_1$

8 = ${r × (100 - 10)}/100 - 10$

8 = ${r × 90}/100 - 10$

8 = ${r × 9}/10$ = 20%

Question : 4

What price should a shopkeeper mark on an article costing him Rs.200 to gain 35% after allowing a discount of 25% ?

a) Rs.300

b) Rs.360

c) Rs.330

d) Rs.270

Answer: (b)

Let the marked price be x.

${x × 75}/100 = 200 × 135/100$

$x = {200 × 135}/75$ = Rs.360

Using Rule 9,
The marked price of an article is fixed in such a way that after allowing a discount of r% a profit of R% is obtained. Then the marked price of the article is $({r + R}/{100 - r} × 100)$% more than its cost price.

Here, r = 25%, R = 35%, C.P. = Rs.200

Marked price

= Rs.$200 + 200 × ({r + R}/{100 - r} × 100)$%

= $200 + 200 × ({25 + 35}/{100 - 25})$ × 100%

= 200 + ${200 × 60}/75 × 100%$

= 200 + ${200 × 20 × 4}/100$

= 200 + 160 = Rs.360

Question : 5

A trader marks his goods 40% above cost price and allows a discount of 25 %. The profit he makes, is :

a) 10 %

b) 2 %

c) 5 %

d) 15%

Answer: (c)

Let the cost price be Rs.100.

Marked price = Rs.140

S.P. = ${75 × 140}/100$ = Rs.105

Profit per cent = 5%

Using Rule 8,

Here, r = 40%, $r_1$ = 25%

Profit % = ${r × (100 - r_1)}/100 - r_1$

= ${40 × (100 - 25)}/100 - 25$

= ${40 × 75}/100 - 25$

= $3000/100$ - 25

= 30 - 25 = 5%

Question : 6

If a shopkeeper marks the price of goods 50% more than their cost price and allows a discount of 40%, what is his gain or loss percent ?

a) Loss of 10%

b) Loss of 20%

c) Gain of 20%

d) Gain of 10%

Answer: (a)

C.P. of article = Rs.100

Marked price = Rs.150

S.P. = ${150 × 60}/100$ = Rs.90

Loss = 100 - 90 = Rs.10 i.e. 10%

Using Rule 8,

Here, r = 50%, $r_1$ = 40%

His loss % = ${r × (100 - r_1)}/100 - r_1$

= ${50 × (100 - 40)}/100 - 40$

= ${50 × 60}/100 - 40$

= –10% (–ve sign shows loss)

= 10% loss

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