model 2 hiking & discounting Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 4 EXERCISES

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The following question based on discount topic of quantitative aptitude

Questions : If a shopkeeper marks the price of goods 50% more than their cost price and allows a discount of 40%, what is his gain or loss percent ?

(a) Loss of 10%

(b) Loss of 20%

(c) Gain of 20%

(d) Gain of 10%

The correct answers to the above question in:

Answer: (a)

C.P. of article = Rs.100

Marked price = Rs.150

S.P. = ${150 × 60}/100$ = Rs.90

Loss = 100 - 90 = Rs.10 i.e. 10%

Using Rule 8,

Here, r = 50%, $r_1$ = 40%

His loss % = ${r × (100 - r_1)}/100 - r_1$

= ${50 × (100 - 40)}/100 - 40$

= ${50 × 60}/100 - 40$

= –10% (–ve sign shows loss)

= 10% loss

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Question : 1

A trader marks his goods 40% above cost price and allows a discount of 25 %. The profit he makes, is :

a) 10 %

b) 2 %

c) 5 %

d) 15%

Answer: (c)

Let the cost price be Rs.100.

Marked price = Rs.140

S.P. = ${75 × 140}/100$ = Rs.105

Profit per cent = 5%

Using Rule 8,

Here, r = 40%, $r_1$ = 25%

Profit % = ${r × (100 - r_1)}/100 - r_1$

= ${40 × (100 - 25)}/100 - 25$

= ${40 × 75}/100 - 25$

= $3000/100$ - 25

= 30 - 25 = 5%

Question : 2

What price should a shopkeeper mark on an article costing him Rs.200 to gain 35% after allowing a discount of 25% ?

a) Rs.300

b) Rs.360

c) Rs.330

d) Rs.270

Answer: (b)

Let the marked price be x.

${x × 75}/100 = 200 × 135/100$

$x = {200 × 135}/75$ = Rs.360

Using Rule 9,
The marked price of an article is fixed in such a way that after allowing a discount of r% a profit of R% is obtained. Then the marked price of the article is $({r + R}/{100 - r} × 100)$% more than its cost price.

Here, r = 25%, R = 35%, C.P. = Rs.200

Marked price

= Rs.$200 + 200 × ({r + R}/{100 - r} × 100)$%

= $200 + 200 × ({25 + 35}/{100 - 25})$ × 100%

= 200 + ${200 × 60}/75 × 100%$

= 200 + ${200 × 20 × 4}/100$

= 200 + 160 = Rs.360

Question : 3

The marked price of an article is Rs.500. A shopkeeper gives a discount of 5% and still makes a profit of 25%. The cost price of the article is.

a) Rs.380

b) Rs.376

c) Rs.300

d) Rs.384

Answer: (a)

Cost price of the article = Rs.x

$x × 125/100 = {500 × 95}/100$

$x = {500 × 95}/125$ = Rs.380

Using Rule 6,

Here, R = 25%, D = 5%, M.P. = Rs.500, C.P. = ?

$\text"M.P."/\text"C.P."= {100 + r}/{100 - D}$

$500/\text"C.P."= {100 + 25}/{100 - 5}$

C.P. = ${500 × 95}/125$ = Rs.38

Question : 4

In a shop, shirts are usually sold at 40% above the cost price. During a sale, the shopkeeper offers a discount of 10% off the usual selling price. If he manages to sell 72 shirts for Rs.13,608, then his cost price per shirt, (in Rs.) is

a) 150

b) 125

c) 149

d) 210

Answer: (a)

Let the CP of each shirt be Rs.100,

then SP = Rs.140.

New SP = ${140 × 90}/100$ = Rs.126

When S.P. is Rs.126,

C.P. = Rs.100

When S.P. is Rs.$13608/72$,

then C.P. = $100/126 × 13608/72$ = Rs.150

Question : 5

A seller marks his goods 30% above their cost price but allows 15% discount for cash payment. His percentage of profit when sold in cash is

a) 15%

b) 8.5%

c) 9%

d) 10.5%

Answer: (d)

Let the C.P. be Rs.100

Marked price = Rs.130

S.P. = 85% of Rs.130

= Rs.$({85 × 130}/100)$ = Rs.110.5

Gain percent = 10.5%

Using Rule 8,

Here, r = 30%, $r_1$ = 15%

Profit % = ${r × (100 - r_1)}/100 - r_1$

= ${30 × (100 - 15)}/100 - 15$

= ${30 × 85}/100$ - 15

= 25.5 - 15 = 10.5%

Question : 6

How much percent above the cost price should a shopkeeper mark his goods so as to earn a profit of 32% after allowing a discount of 12% on the marked price ?

a) 40%

b) 45%

c) 60%

d) 50%

Answer: (d)

Let the C.P. be Rs.100

and the marked price be Rs.x.

$x × 88/100$ = 132

$x = {132 × 100}/88$

= 150 i.e., more by 50%

Required percentage = 50%

Using Rule 8,
A tradesman marks his goods r% above his cost price. If he allows his customers a discount of $r_1$% on the marked price. Then is profit or loss per cent is
${r × (100 - r_1)}/100 - r_1$
(Positive sign signifies profit and negative sign signifies loss).

Here, Gain % = 32%, $r_1$ = 12%, r = ?

Gain % = ${r × (100 - r_1)}/100 - r_1$

32 = ${r × (100 - 12)}/100 - 12$

44 = ${r × 88}/100$

r = 50%

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