model 2 hiking & discounting Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 4 EXERCISES

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The following question based on discount topic of quantitative aptitude

Questions : A trademan marks his goods at 20% above the cost price. He allows his customers a discount of 8% on marked price. Find out his profit per cent.

(a) 10.4%

(b) 8.2%

(c) 8.6%

(d) 12%

The correct answers to the above question in:

Answer: (a)

Suppose C.P. = 100

On 20% above S.P. = 120

On discount of 8%

= $120 - 120 × 8/100$

= $120 - 48/5$ = 120 - 9.6 = 110.4

Gain = 110.4 - 100 = 10.4%

Using Rule 8,

Here, r = 20%, $r_1$ = 8%

Profit or loss

= ${r × (100 - r_1)}/100 - r_1$

= ${20 × (100 - 8)}/100 - 8$

= ${20 × 92}/100 - 8$

= 18.4 - 8 = 10.4% profit

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Read more based on hiking and discounting Based Quantitative Aptitude Questions and Answers

Question : 1

Jasmine allows 4% discount on the marked price of her goods and still earns a profit of 20%. What is the cost price of a shirt if its marked price is Rs.850?

a) Rs.720

b) Rs.680

c) Rs.700

d) Rs.650

Answer: (b)

Cost price of the shirt = Rs.x

$x × 120/100 = {850 × 96}/100$

x × 120 = 850 × 96

$x = {850 × 96}/120$ = Rs.680

Using Rule 6,
If r% of profit or loss occur after giving D% discount on marked price, then
$\text"MP"/\text"CP" = {100 ± r}/{100 - D}$
(positive sign for profit and negative for loss)

Here r = 20%, D = 4%, M.P. = Rs.850, C.P. = ?

$\text"M.P."/\text"C.P."= {100 + r}/{100 - D}$

$850/\text"C.P." = {100 + 20}/{100 - 4}$

C.P. = ${850 × 96}/120$

C.P. = Rs.680

Question : 2

Anand marks up the price of an article by 50% and then allows a discount of 20% and sells it to Balaji. Balaji sells it for Rs.20 more than what he purchased for, this S.P is 30% more than the original C.P of the article. Then Balaji's profit % is

a) 6.66%

b) 9%

c) 8.33%

d) 7.5%

Answer: (c)

For Anand,

Cost price = Rs.x

Marked price = Rs.$3/2$x

Selling price

= ${3x}/2 × 80/100$ = Rs.${6x}/5$

For Balaji,

Cost price = Rs.${6x}/5$

Selling price = Rs.$({6x}/5 + 20)$

${6x}/5 + 20 = {x × 130}/100$

${13x}/10 - {6x}/5 = 20$

${13x - 12x}/10 = 20$

$x/10$ = 20 ⇒ x = Rs.200

Required gain percent

= $20/{{6x}/5} × 100$

= ${20 × 5 × 100}/{6 × 200} = 25/3 =8.33%$

Question : 3

How much percent above the cost price should a shopkeeper mark his goods so as to earn a profit of 32% after allowing a discount of 12% on the marked price ?

a) 40%

b) 45%

c) 60%

d) 50%

Answer: (d)

Let the C.P. be Rs.100

and the marked price be Rs.x.

$x × 88/100$ = 132

$x = {132 × 100}/88$

= 150 i.e., more by 50%

Required percentage = 50%

Using Rule 8,
A tradesman marks his goods r% above his cost price. If he allows his customers a discount of $r_1$% on the marked price. Then is profit or loss per cent is
${r × (100 - r_1)}/100 - r_1$
(Positive sign signifies profit and negative sign signifies loss).

Here, Gain % = 32%, $r_1$ = 12%, r = ?

Gain % = ${r × (100 - r_1)}/100 - r_1$

32 = ${r × (100 - 12)}/100 - 12$

44 = ${r × 88}/100$

r = 50%

Question : 4

A trader marks his goods45% above the cost price and gives a discount of 20% on the marked price. The gain % on goods he makes is :

a) 14%

b) 16%

c) 29%

d) 15%

Answer: (b)

Let the C.P. of article be Rs.100

Marked price = Rs.145

S.P. = ${145 × 80}/100$ = Rs.116

Profit percent = 16%

Using Rule 8,

Here, r = 45%, $r_1$ = 20%

Gain % = ${r × (100 - r_1)}/100 - r_1$

= ${45 × (100 - 20)}/100 - 20$

= $3600/100$ - 20

= 36 - 20 = 16%

Question : 5

A trader marked the selling price of an article at 10% above the cost price. At the time of selling, he allows certain discount and suffers a loss of 1%. He allowed the discount of :

a) 10%

b) 10.5%

c) 9%

d) 11%

Answer: (a)

Let C.P. be 100

Marked price = 110

x% of 110 = 11

x = ${11 × 100}/110$ = 10%

Using Rule 8,

Here, loss % = 1%, r = 10%, $r_1$ = x%

loss % = ${r × (100 - r_1)}/100 - r_1$

–1 = ${100 × (100 - x)}/100 - x$

(–ve sign for loss)

–100 = 1000 - 10x - 100x

+110x = 1100

x = 10% ⇒ r1 =10%

Question : 6

A tradesman marks his goods 10% above his cost price. If he allows his customers 10% discount on the marked price, how much profit or loss does he make, if any?

a) 1%loss

b) No gain, no loss

c) 5% gain

d) 1% gain

Answer: (a)

Required loss [As per Rule]

= $({10 × 10}/100)$% = 1%

Using Rule 8,
A tradesman marks his goods r% above his cost price. If he allows his customers a discount of $r_1$% on the marked price. Then is profit or loss per cent is
${r × (100 - r_1)}/100 - r_1$
(Positive sign signifies profit and negative sign signifies loss).

Here, r = 10% and $r_1$ = 10%

Required profit or loss

= ${r × (100 - r_1)}/100 - r_1$

= ${10 × (100 - 10)}/100 - 10$

= 9 - 10

= –1% (–ve sign shows loss) = 1% loss

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