find distance only section 6 Detailed Explanation And More Example
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The following question based on direction & distance sense test topic of verbal reasoning
(a) 4 km
(b) 2 km
(c) 8 km
(d) 6 km
The correct answers to the above question in:
Answer: (b)
Required distance = AF
= 2 km
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Read more type 2 section 6 mcqs Based Verbal Reasoning Questions and Answers
Question : 1
Rahul travelled from a point and straightly goes to point ‘Y’ at a distance of 90 metres. He turned right and walked 40 metres, then again turned right and walked 70 metres. Finally, he turned right and walked 40 metres. How far he is from the starting point ?
a) 10 metres
b) 30 metres
c) 70 metres
d) 20 metres
Answer »Answer: (d)
Required distance = AE
= 20 metre
Question : 2
Jai Prakash started walking towards south from the point A, walked 20 m and reached a point B, Again, he turned left and walked 20 m and reached a point C. Now he turned 45° anticlockwise, walked a distance of 20 √2 m and reached a point D. What approximately is the shortest distance between the point A and D?
a) 30 m
b) 40$√{2}$ m
c) Can't say
d) 40 m
Answer »Answer: (d)
Here, AC = $√{20^2 + 20^2} = 20$√{2}$ m
Since AB = BC
∴ ∠ACB = ∠BAC = 45°
∴ ∠ACD = 90°
Now,
AD2 = AC2 + CD2
= 800 + 800 = 1600
∴ AD = $√{1600}$ = 40 m
Question : 3
A man walks 1 km towards East and then he turns to South and walks 5 km. Again he turns to East and walks 2 km, after this he turns to North and walks 9 km. Now, how far is he from his starting point ?
a) 5 km
b) 4 km
c) 3 km
d) 7 km
Answer »Answer: (a)
The movements of the man are as shown in the figure,
(A to B, B to C, C to D, D to E)
Clearly, DF = BC = 5km.
EF = (DE - DF) = (9 - 5)km = 4km.
BF = CD = 2km
AF =AB + BF = AB + CD = (1 + 2)km = 3km.
∴ Man's distance from initial position A
= AE = $√{AF^2 + FE^2}$
= $√{3^2 + 4^2}$
= $√25$ = 5m.
Question : 4
If Sita walks 10 km towards West, then turned towards South and walked 10 km, then turned East walked 10 km, and turned North walked 10 km. How far she is from starting point?
a) 0 km
b) 20 km
c) 40 km
d) 10 km
Answer »Answer: (a)
Question : 5
An insect is walking in a straight line. It covers a distance of 15 cm per minute. It comes back 2.5 cm after every 15 cm. How long will it take to cover a distance of 1 metre ?
a) 8 min
b) 12 min
c) 6.5 min
d) 10 min
Answer »Answer: (a)
The insect covers 15 – 2.5 = 12.5 cm in one minute.
So, it will cover 1 metre (= 100 cm) in $100/12.5$ = 8 minutes
Question : 6
Raju drives 25 km North and turns left and travels 5 km and reaches point ‘O’. He then turns right and covers another 5 kms. Afterwards turns to east and drives 5 km. How much distance he has to travel to go back to the starting point?
a) 25 kms
b) 20 kms
c) 35 kms
d) 30 kms
Answer »Answer: (d)
Required distance AD
= (25 + 5) km = 30 km
GET direction & distance sense test PRACTICE TEST EXERCISES
find directions only
find distance only
find both direction & distance
find directions only section 2
find directions only section 3
find directions only section 4
find directions only section 5
find directions only section 6
find distance only section 2
find distance only section 3
find distance only section 4
find distance only section 5
find distance only section 6
find both direction & distance section 2
find both direction & distance section 3
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