find distance only section 5 Detailed Explanation And More Example
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The following question based on direction & distance sense test topic of verbal reasoning
(a) 900
(b) 500
(c) 1300
(d) 800
The correct answers to the above question in:
Answer: (b)
Required distance AE = AD + DE
= (400 + 100) metres
= 500 metres
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Read more type 2 section 5 mcqs Based Verbal Reasoning Questions and Answers
Question : 1
A girl rides her bicycle southwards, then turned right and rode 2 km and again turned right and rode 4 km. She found himself exactly 2 km east from the starting point. How far did she ride southwards initially?
a) 3 km
b) 4 km
c) 2km
d) 6 km
e) None of these
Answer »Answer: (b)
Question : 2
From a point, Sahil starts walking in east direction. After walking for 15 m he takes a right turn. Now he walks for 12 m before turning to his right again. Next he walks 5 m and again turns in same direction as before. He now walks for 20 m before stopping at a point. How far is this point from the point where Sahil started?
a) $3√22 m$
b) 7 m
c) $4√10 m$
d) $2√41 m$
e) 12 m
Answer »Answer: (d)
Required distance =$√(10^2 + 8^2 )= 2√41 m$
Question : 3
A man walks 6 km towards the north, then turns towards his left and walks for 4 km. He again turns left and walks for 6 km. At this point he turns to his right and walks for 6 km. How many km and in what direction is he from the starting point ?
a) 6 km and South
b) 8 km and West
c) 10 km and West
d) 4 km and South
Answer »Answer: (c)
It is clear from the diagram that the man is 10 km towards west from the starting point.
Question : 4
A person starts from a point A and travels 3 km east - wards to B and then turns left and travels thrice that distance to reach C. He again turns left and travels five times the distance he covered between A and B and reaches his destination D. The shortest distance between the starting point and the destination is ?
a) 16 km
b) 12 km
c) 15 km
d) 18 km
e) None of these
Answer »Answer: (c)
The movements of the person are as shown in Figure
Clearly, AB = 3 km,
BC = 3AB = (3 × 3) km = 9 km,
CD = 5AB = (5 × 3) km = 15 km,
Draw AE ⊥ CD.
Then, CE = AB = 3 km and AE = BC = 9 km
DE = (CD – CE) = (15 – 3) km = 12 km.
In ΔAED, AD2 = AE2 + DE2
⇒ AD = $√{( 9^2 +(12)^2 }$km = $√225$ km
Required distance = AD = 15 km
Question : 5
Suhas travelled 15 km. towards East, then turned towards North and travelled 15 km and turned towards West and travelled 15 km. How far is he from the starting point ?
a) 30 km
b) 0 km
c) 15 km
d) 45 km
Answer »Answer: (c)
Required distance = AD = 15 km
Question : 6
Laxmi went 10 km to the West from my house, then turned left and walked 20 kms. She then turned East and walked 25 kms and finally turning left covered 20 kms. How far was she from my house?
a) 10 kms
b) 40 kms
c) 5 kms
d) 15 kms
Answer »Answer: (d)
GET direction & distance sense test PRACTICE TEST EXERCISES
find directions only
find distance only
find both direction & distance
find directions only section 2
find directions only section 3
find directions only section 4
find directions only section 5
find directions only section 6
find distance only section 2
find distance only section 3
find distance only section 4
find distance only section 5
find distance only section 6
find both direction & distance section 2
find both direction & distance section 3
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