find distance only section 5 Detailed Explanation And More Example

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The following question based on direction & distance sense test topic of verbal reasoning

Questions : Kashish goes 30 metres North, then turns right and walks 40 metres, then again turns right and walks 20 metres, then again turns right and walks 40 metres. How many metres is he from his original position ?

(a) 20

(b) 10

(c) 0

(d) 40

The correct answers to the above question in:

Answer: (b)

direction-and-distance-verbal-reasoning

The movements of Kashish are as shown in Figure.

(A to b, B to C, C to D, D to E)

∴ Kashish's distance from his original position

A = AE = (AB - BE) = (AB - CD)

= (30 - 20) = 10m.

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Read more type 2 section 5 mcqs Based Verbal Reasoning Questions and Answers

Question : 1

Karthik travelled 3 km east, then took a right turn and travelled 4 kms. How far is he from starting point ?

a) 12 kms

b) 7 kms

c) 5 kms

d) 3 kms

Answer: (c)

direction-and-distance-verbal-reasoning

Required distance

AC = $√{AB^2 + BC^2}$

= $√{3^2 + 4^2}$

= $√{9 + 16}$

= $√{25}$ 

= 5 km

Question : 2

A postman starts delivering letters 3 km southwards and then turns right. He covers 4 km on this road and again turns right. He delivers letters for 3 km and completes his daily beat. Then, he turns left for lunch at home, which is 5 km away. How far has he to travel to reach the post-office after lunch ?

a) 10 km

b) 8 km

c) 15 km

d) 9 km

Answer: (c)

direction-and-distance-verbal-reasoning

Required distance

= AE = AD + DE

= 4 km + 5 km = 9 km

Question : 3

A and B start walking from the same point. A goes north and covers 3 km, then turns right and covers 4 kms. B goes west and covers 5 kms, then turns right and covers 3 kms. How far apart are they from each other ?

a) 9 km

b) 5 km

c) 10 km

d) 8 km

Answer: (a)

direction-and-distance-verbal-reasoning

Required distance

= (5 + 4) km

= 9 km

Question : 4

A man travels 4 km due north, then travels 6 km due east and further travels 4 km due north. How far he is from the starting point ?

a) 10 km

b) 14 km

c) 8 km

d) 6 km

Answer: (a)

direction-and-distance-verbal-reasoning

Required distance

AD = $√{DE^2 + AE^2}$

= $√{8^2 + 6^2}$

= $√{64+ 36}$

= $√{100}$ = 10 km

Question : 5

A person starts from point T in east direction. Walks 6 m and turns right. Next walks 4 m and turns left. Next walks 3m and turns right. Now cycles for 8 km and stops. Find his distance from T.

a) $2√31 m$

b) 15 m

c) 17 m

d) $7√21 m$

e) 12 m

Answer: (b)

Distance = $√[(6+3)^2 + (4+8)^2 ] = 15 m$

Question : 6

A man travels 3 km in the East and turns to South and moves 4 km. How far is he from the starting point ?

a) 6 km

b) 10 km

c) 5 km

d) 2 km

Answer: (c)

direction-and-distance-verbal-reasoning

direction-and-distance-verbal-reasoning

AC = $√{AB^2 + BC^2}$

= $√{3^2 + 4^2}$

= $√{9+ 16}$

= $√{25}$ = 5 km

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