find distance only section 4 Detailed Explanation And More Example

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The following question based on direction & distance sense test topic of verbal reasoning

Questions : Gaurav walks 20 metres towards North. He then turns left and walks 40 metres. He again turns left and walks 20 metres. Further, he moves 20 metres after turning to the right. How far is he from his original position ?

(a) 50 metres

(b) 30 metres

(c) 20 metres

(d) 60 metres

e) None of these

The correct answers to the above question in:

Answer: (d)

direction-and-distance-verbal-reasoning

The movements of Gaurav are as shown in Figure.

Clearly, Gaurav's distance from his initial position

P = PX = (PS + SX) = (QR + SX)

= (40 + 20)m = 60m.

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Read more type 2 section 4 mcqs Based Verbal Reasoning Questions and Answers

Question : 1

A, B, C, D and E are standing in a line facing North. E is standing 40 metres left to B. A is standing 20 metres left to C. D is standing 20 metres right to E and 50 metres right to C. What is the distance between A and D ?

a) 60 metres

b) 80 metres

c) 50 metres

d) 70 metres

Answer: (d)

direction-and-distance-verbal-reasoning

AD = (20 + 30 + 20)m = 70m

Question : 2

Rama is standing at a point facing north. He walks 10 km straight, turns left and walks another 15 km straight and finally turns left and walks 10 km. How far is he from the starting points now ?

a) 5 km

b) 15 km

c) 10 km

d) 12 km

Answer: (b)

direction-and-distance-verbal-reasoning

Required distance = 15 km

Question : 3

Mohan travelled from point ‘A’ straight to ‘B’ at a distance of 8 m. He turned right and walked 4m, again turned to his right and walked 8 m. Finally he turned to his right and walked 3 m. How far he was from his starting point?

a) 3 m

b) 4 m

c) 8 m

d) 1 m

Answer: (d)

direction-and-distance-verbal-reasoning

Required distance = 1 km

Question : 4

travelled from a point X straight to Y at a distance of 80 metres. He turned right and walked 50 metres, then again turned right and walked 70 metres. Finally, he turned right and walked 50 metres. How far is he from the starting point ?

a) 50 metres

b) 20 metres

c) 10 metres

d) 70 metres

e) None of these

Answer: (c)

direction-and-distance-verbal-reasoning

The movements of Raj are as shown in the figure,

(X to Y, Y to A, A to B, B to C)

∴  Raj's distnace from the starting point X

= XC = (XY - YC)

= (XY - BA)

= (80 - 70) = 10m.

Question : 5

Kashish goes 30 metres North, then turns right and walks 40 metres, then again turns right and walks 20 metres, then again turns right and walks 40 metres. How many metres is he from his original position?

a) 10

b) 40

c) 0

d) 20

Answer: (a)

direction-and-distance

The movements of Kashish are as shown in figure (A to B, B to C, C to D, D to E).

So, Kashish’s distance from his original position A = AE

AE = (AB – BE) = (AB – CD) = (30 – 20) m = 10 m.

Question : 6

A person starts from a point and goes 6 km in north direction. Now he takes a right turn and moves 7 km. Next he takes a left turn and moves 10 km. Next he turns right and moves 5 km. Finally he turns right and moves 12 km to reach his destination. Find the distance from his starting point.

a) $4√10 km$

b) $5√5 km$

c) 12 km

d) $6√2 km$

e) None of these

Answer: (a)

Required distance is $√(12^2 + 4^2 ) = 4√10 km$.

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