find distance only section 4 Detailed Explanation And More Example
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The following question based on direction & distance sense test topic of verbal reasoning
(a) 50 metres
(b) 20 metres
(c) 10 metres
(d) 70 metres
e) None of these
The correct answers to the above question in:
Answer: (c)
The movements of Raj are as shown in the figure,
(X to Y, Y to A, A to B, B to C)
∴ Raj's distnace from the starting point X
= XC = (XY - YC)
= (XY - BA)
= (80 - 70) = 10m.
Discuss Form
Read more type 2 section 4 mcqs Based Verbal Reasoning Questions and Answers
Question : 1
Gaurav walks 20 metres towards North. He then turns left and walks 40 metres. He again turns left and walks 20 metres. Further, he moves 20 metres after turning to the right. How far is he from his original position ?
a) 50 metres
b) 30 metres
c) 20 metres
d) 60 metres
e) None of these
Answer »Answer: (d)
The movements of Gaurav are as shown in Figure.
Clearly, Gaurav's distance from his initial position
P = PX = (PS + SX) = (QR + SX)
= (40 + 20)m = 60m.
Question : 2
A, B, C, D and E are standing in a line facing North. E is standing 40 metres left to B. A is standing 20 metres left to C. D is standing 20 metres right to E and 50 metres right to C. What is the distance between A and D ?
a) 60 metres
b) 80 metres
c) 50 metres
d) 70 metres
Answer »Answer: (d)
AD = (20 + 30 + 20)m = 70m
Question : 3
Rama is standing at a point facing north. He walks 10 km straight, turns left and walks another 15 km straight and finally turns left and walks 10 km. How far is he from the starting points now ?
a) 5 km
b) 15 km
c) 10 km
d) 12 km
Answer »Answer: (b)
Required distance = 15 km
Question : 4
Kashish goes 30 metres North, then turns right and walks 40 metres, then again turns right and walks 20 metres, then again turns right and walks 40 metres. How many metres is he from his original position?
a) 10
b) 40
c) 0
d) 20
Answer »Answer: (a)
The movements of Kashish are as shown in figure (A to B, B to C, C to D, D to E).
So, Kashish’s distance from his original position A = AE
AE = (AB – BE) = (AB – CD) = (30 – 20) m = 10 m.
Question : 5
A person starts from a point and goes 6 km in north direction. Now he takes a right turn and moves 7 km. Next he takes a left turn and moves 10 km. Next he turns right and moves 5 km. Finally he turns right and moves 12 km to reach his destination. Find the distance from his starting point.
a) $4√10 km$
b) $5√5 km$
c) 12 km
d) $6√2 km$
e) None of these
Answer »Answer: (a)
Required distance is $√(12^2 + 4^2 ) = 4√10 km$.
Question : 6
Q walked 20 m towards west, took a left turn and walked 20 m. He then took a right turn and walked 20 m and again took a right turn and walked 20 m. How far is Q now from the starting point ?
a) 40 m
b) 80 m
c) 120 m
d) 50 m
Answer »Answer: (a)
AE = AB + BE
= (20 + 20) metres
= 40 metres
GET direction & distance sense test PRACTICE TEST EXERCISES
find directions only
find distance only
find both direction & distance
find directions only section 2
find directions only section 3
find directions only section 4
find directions only section 5
find directions only section 6
find distance only section 2
find distance only section 3
find distance only section 4
find distance only section 5
find distance only section 6
find both direction & distance section 2
find both direction & distance section 3
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