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The following question based on direction & distance sense test topic of verbal reasoning
(a) $4√10 km$
(b) $5√5 km$
(c) 12 km
(d) $6√2 km$
e) None of these
The correct answers to the above question in:
Answer: (a)
Required distance is $√(12^2 + 4^2 ) = 4√10 km$.
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Read more type 2 section 4 mcqs Based Verbal Reasoning Questions and Answers
Question : 1
Kashish goes 30 metres North, then turns right and walks 40 metres, then again turns right and walks 20 metres, then again turns right and walks 40 metres. How many metres is he from his original position?
a) 10
b) 40
c) 0
d) 20
Answer »Answer: (a)
The movements of Kashish are as shown in figure (A to B, B to C, C to D, D to E).
So, Kashish’s distance from his original position A = AE
AE = (AB – BE) = (AB – CD) = (30 – 20) m = 10 m.
Question : 2
travelled from a point X straight to Y at a distance of 80 metres. He turned right and walked 50 metres, then again turned right and walked 70 metres. Finally, he turned right and walked 50 metres. How far is he from the starting point ?
a) 50 metres
b) 20 metres
c) 10 metres
d) 70 metres
e) None of these
Answer »Answer: (c)
The movements of Raj are as shown in the figure,
(X to Y, Y to A, A to B, B to C)
∴ Raj's distnace from the starting point X
= XC = (XY - YC)
= (XY - BA)
= (80 - 70) = 10m.
Question : 3
Gaurav walks 20 metres towards North. He then turns left and walks 40 metres. He again turns left and walks 20 metres. Further, he moves 20 metres after turning to the right. How far is he from his original position ?
a) 50 metres
b) 30 metres
c) 20 metres
d) 60 metres
e) None of these
Answer »Answer: (d)
The movements of Gaurav are as shown in Figure.
Clearly, Gaurav's distance from his initial position
P = PX = (PS + SX) = (QR + SX)
= (40 + 20)m = 60m.
Question : 4
Q walked 20 m towards west, took a left turn and walked 20 m. He then took a right turn and walked 20 m and again took a right turn and walked 20 m. How far is Q now from the starting point ?
a) 40 m
b) 80 m
c) 120 m
d) 50 m
Answer »Answer: (a)
AE = AB + BE
= (20 + 20) metres
= 40 metres
Question : 5
Sunita rode her scooty northwards, then turned left and then again rode to her left 4 km. She found herself exactly 2 kms West of her starting point. How far did she ride northwards initially?
a) 2 km
b) 5 km
c) 6 km
d) 4 km
Answer »Answer: (d)
Sunita rode 4 km Northwards.
Question : 6
A man starts journey from home. He goes 5 kms to the North, then proceeds 10 kms to the right. From there he again turns right and goes 10 kms. How far is he from home? All distances are measured aerially.
a) 150
b) 125
c) 200
d) 225
Answer »Answer: (b)
Required distance
AE = $√{AD^2 + DE^2}$
= $√{10^2 + 5^2}$
= $√{100+ 25}$
= $√{125}$
GET direction & distance sense test PRACTICE TEST EXERCISES
find directions only
find distance only
find both direction & distance
find directions only section 2
find directions only section 3
find directions only section 4
find directions only section 5
find directions only section 6
find distance only section 2
find distance only section 3
find distance only section 4
find distance only section 5
find distance only section 6
find both direction & distance section 2
find both direction & distance section 3
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