find distance only section 4 Detailed Explanation And More Example

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The following question based on direction & distance sense test topic of verbal reasoning

Questions : A person starts from a point and goes 6 km in north direction. Now he takes a right turn and moves 7 km. Next he takes a left turn and moves 10 km. Next he turns right and moves 5 km. Finally he turns right and moves 12 km to reach his destination. Find the distance from his starting point.

(a) $4√10 km$

(b) $5√5 km$

(c) 12 km

(d) $6√2 km$

e) None of these

The correct answers to the above question in:

Answer: (a)

Required distance is $√(12^2 + 4^2 ) = 4√10 km$.

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Read more type 2 section 4 mcqs Based Verbal Reasoning Questions and Answers

Question : 1

Kashish goes 30 metres North, then turns right and walks 40 metres, then again turns right and walks 20 metres, then again turns right and walks 40 metres. How many metres is he from his original position?

a) 10

b) 40

c) 0

d) 20

Answer: (a)

direction-and-distance

The movements of Kashish are as shown in figure (A to B, B to C, C to D, D to E).

So, Kashish’s distance from his original position A = AE

AE = (AB – BE) = (AB – CD) = (30 – 20) m = 10 m.

Question : 2

travelled from a point X straight to Y at a distance of 80 metres. He turned right and walked 50 metres, then again turned right and walked 70 metres. Finally, he turned right and walked 50 metres. How far is he from the starting point ?

a) 50 metres

b) 20 metres

c) 10 metres

d) 70 metres

e) None of these

Answer: (c)

direction-and-distance-verbal-reasoning

The movements of Raj are as shown in the figure,

(X to Y, Y to A, A to B, B to C)

∴  Raj's distnace from the starting point X

= XC = (XY - YC)

= (XY - BA)

= (80 - 70) = 10m.

Question : 3

Gaurav walks 20 metres towards North. He then turns left and walks 40 metres. He again turns left and walks 20 metres. Further, he moves 20 metres after turning to the right. How far is he from his original position ?

a) 50 metres

b) 30 metres

c) 20 metres

d) 60 metres

e) None of these

Answer: (d)

direction-and-distance-verbal-reasoning

The movements of Gaurav are as shown in Figure.

Clearly, Gaurav's distance from his initial position

P = PX = (PS + SX) = (QR + SX)

= (40 + 20)m = 60m.

Question : 4

Q walked 20 m towards west, took a left turn and walked 20 m. He then took a right turn and walked 20 m and again took a right turn and walked 20 m. How far is Q now from the starting point ?

a) 40 m

b) 80 m

c) 120 m

d) 50 m

Answer: (a)

direction-and-distance-verbal-reasoning

AE = AB + BE

= (20 + 20) metres

= 40 metres

Question : 5

Sunita rode her scooty northwards, then turned left and then again rode to her left 4 km. She found herself exactly 2 kms West of her starting point. How far did she ride northwards initially?

a) 2 km

b) 5 km

c) 6 km

d) 4 km

Answer: (d)

direction-and-distance-verbal-reasoning

Sunita rode 4 km Northwards.

Question : 6

A man starts journey from home. He goes 5 kms to the North, then proceeds 10 kms to the right. From there he again turns right and goes 10 kms. How far is he from home? All distances are measured aerially.

a) 150

b) 125

c) 200

d) 225

Answer: (b)

direction-and-distance-verbal-reasoning

Required distance

AE = $√{AD^2 + DE^2}$

= $√{10^2 + 5^2}$

= $√{100+ 25}$

= $√{125}$

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