find distance only section 3 Detailed Explanation And More Example

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The following question based on direction & distance sense test topic of verbal reasoning

Questions : Arjun starts from school and walks 4 km towards West, turns right and walks 3 km. Then he planned to return back to school, but only in the shortest path. What is the shortest distance between the school and the point where he stopped ?

(a) 16 km

(b) 5 km

(c) 3 km

(d) 25 km

The correct answers to the above question in:

Answer: (b)

direction-and-distance-verbal-reasoning

Required distance

AC = $√{AB^2 + BC^2}$

= $√{4^2 + 3^2}$

= $√{16+ 9}$

= $√{25}$ 

= 5 km

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Read more type 2 section 3 mcqs Based Verbal Reasoning Questions and Answers

Question : 1

Namita walks 14 metres towards west, then turns to her right and walks 14 metres and then turns to her left and walks 10 metres. Again turning to her left she walks 14 metres. What is the shortest distance (in metres) between her starting point and the present position?

a) 28

b) 10

c) 24

d) 38

e) None of these

Answer: (c)

direction-and-distance

Required answer: DA + SA = 10 + 14 = 24m.

Question : 2

A, B, C, D and E are standing in a line facing North. E is standing 40 metres left to B. A is standing 20 metres left to C. D is standing 20 metres right to E and 50 metres right to C. What is the distance between A and B ?

a) 80 metres

b) 100 metres

c) 70 metres

d) 90 metres

Answer: (d)

direction-and-distance-verbal-reasoning

AB = (20 + 30 + 20 + 20) m

= 90 metres

Question : 3

A man walks 30 metres towards South. Then, turning to his right, he walks 30 metres. Then, turning to his left, he walks 20 metres. Again, he turns to his left and walks 30 metres. How far is he from his initial position ?

a) 60 metres

b) 30 metres

c) 20 metres

d) 80 metres

e) None of these

Answer: (e)

direction-and-distance-verbal-reasoning

The movements of the man are as shown in the figure,

∴ Man's distance from initial position A

= AE = (AB + BE) = (AB + CD)

= (30 + 20) = 50m.

Question : 4

A person starts from a point in east direction. He walks 6 km and turns to his left. Next he walks 4 km and turns to his left again. Next he walks 2 km and turns towards south direction. He stops after walking 8 km. Find his distance from the starting point.

a) $3√2 km$

b) $4√2 km$

c) 16 km

d) $4√4 km$

e) 8 km

Answer: (b)

Required distance = $√ (4^2 + 4^2 ) = 4√2 km$

Question : 5

A house faces North. A man coming out of his house walked straight for 10 metres, turned left and walked 25 metres. He then turned right and walked 5 metres and again turned right and walked 25 metres. How far is he from his house?

a) 55 metres

b) 65 metres

c) 15 metres

d) 60 metres

Answer: (c)

direction-and-distance-verbal-reasoning

Required distance

= AE = AB + BE

= (10 + 5) metres

= 15 metres

Question : 6

Two men start walking from one point towards opposite direction. After walking 3 km straight the both turn right wards and walk straight for the distance of 4km. How far are they both from each-other?

a) 7 km

b) 10 km

c) 8 km

d) 9 km

Answer: (b)

direction-and-distance

In Δ ABC, AC = $√{(AB)^2 + (BC)^2}$

= $√{(3)^2 + (4)^2}$ = $√{9 + 16}$ = $√{25}$ = 5 km

In Δ ADE, AE = $√{(AD)^2 + (DE)^2}$

= $√{(3)^2 + (4)^2}$ = $√{9 + 16}$ = $√{25}$ = 5 km

Hence, CE = 5 + 5 = 10 km

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