find distance only section 3 Detailed Explanation And More Example

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The following question based on direction & distance sense test topic of verbal reasoning

Questions : A man starts from a point and moves 3 km North, then turns to West and goes 2 km. He turns North and walks 1 km and then moves 5 km towards East. How far is he from the starting point?

(a) 10 km.

(b) 5 km

(c) 11 km.

(d) 8 km.

The correct answers to the above question in:

Answer: (b)

direction-and-distance-verbal-reasoning

Required distance

AE = $√{AF^2 + EF^2}$

= $√{4^2 + 3^2}$

= $√{16 + 9}$

= $√{25}$

= 5 km

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Read more type 2 section 3 mcqs Based Verbal Reasoning Questions and Answers

Question : 1

X goes 15 metres North, then turns right and walks 20 metres, then again turns right and walks 10 metres then again turns right and walks 20 metres. How many metres is he from his original position ?

a) 10 m

b) 20 m

c) 5 m

d) 15 m

Answer: (c)

direction-and-distance-verbal-reasoning

Required distance

= 15 – 10 = 5m

Question : 2

Two men start walking from one point towards opposite direction. After walking 3 km straight the both turn right wards and walk straight for the distance of 4km. How far are they both from each-other?

a) 7 km

b) 10 km

c) 8 km

d) 9 km

Answer: (b)

direction-and-distance

In Δ ABC, AC = $√{(AB)^2 + (BC)^2}$

= $√{(3)^2 + (4)^2}$ = $√{9 + 16}$ = $√{25}$ = 5 km

In Δ ADE, AE = $√{(AD)^2 + (DE)^2}$

= $√{(3)^2 + (4)^2}$ = $√{9 + 16}$ = $√{25}$ = 5 km

Hence, CE = 5 + 5 = 10 km

Question : 3

A house faces North. A man coming out of his house walked straight for 10 metres, turned left and walked 25 metres. He then turned right and walked 5 metres and again turned right and walked 25 metres. How far is he from his house?

a) 55 metres

b) 65 metres

c) 15 metres

d) 60 metres

Answer: (c)

direction-and-distance-verbal-reasoning

Required distance

= AE = AB + BE

= (10 + 5) metres

= 15 metres

Question : 4

Deepak walks 20 metres towards North. He then turns left and walks 40 metres. He again turns left and walks 20 metres. Further he moves 20 metres after turning to the right. How far is he from his original position ?

a) 60 mts.

b) 30 mts

c) 20 mts.

d) 50 mts.

Answer: (a)

direction-and-distance-verbal-reasoning

Required distance = AE = AD + DE

= (40 + 20) metres

= 60 metres

Question : 5

Riya started from her home to office. She started in east direction. After walking for 4 m she turned to her left and walked 8 m, now she turned left and walked 2 m. After this she turned to right walked 4 m. Now after turning to her right she walked 13 m and reached office. Find the shortest distance between her office and home.

a) $9√41 m$

b) 26 m

c) 87 m

d) $3√41 m$

e) None of these

Answer: (d)

Question : 6

Maya starts at point T, walks straight towards North to point U which is 4 ft away. She turns left at 90º and walks 1 ft to Q, turns left at 90º and goes to V, who is 1 ft away and once again turns 907deg; right and goes to R, 3 ft away. What is the distance between T and R?

a) 5 ft

b) 8 ft

c) 4 ft

d) 7 ft

Answer: (a)

The movements of Maya from T to R are as shown in figure.

RT = $√{(RV')^2 +(TV')^2}$ = $√{16 + 9}$ = 5ft

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