find distance only section 3 Detailed Explanation And More Example
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The following question based on direction & distance sense test topic of verbal reasoning
(a) 60 mts.
(b) 30 mts
(c) 20 mts.
(d) 50 mts.
The correct answers to the above question in:
Answer: (a)
Required distance = AE = AD + DE
= (40 + 20) metres
= 60 metres
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Read more type 2 section 3 mcqs Based Verbal Reasoning Questions and Answers
Question : 1
A man starts from a point and moves 3 km North, then turns to West and goes 2 km. He turns North and walks 1 km and then moves 5 km towards East. How far is he from the starting point?
a) 10 km.
b) 5 km
c) 11 km.
d) 8 km.
Answer »Answer: (b)
Required distance
AE = $√{AF^2 + EF^2}$
= $√{4^2 + 3^2}$
= $√{16 + 9}$
= $√{25}$
= 5 km
Question : 2
X goes 15 metres North, then turns right and walks 20 metres, then again turns right and walks 10 metres then again turns right and walks 20 metres. How many metres is he from his original position ?
a) 10 m
b) 20 m
c) 5 m
d) 15 m
Answer »Answer: (c)
Required distance
= 15 – 10 = 5m
Question : 3
Two men start walking from one point towards opposite direction. After walking 3 km straight the both turn right wards and walk straight for the distance of 4km. How far are they both from each-other?
a) 7 km
b) 10 km
c) 8 km
d) 9 km
Answer »Answer: (b)
In Δ ABC, AC = $√{(AB)^2 + (BC)^2}$
= $√{(3)^2 + (4)^2}$ = $√{9 + 16}$ = $√{25}$ = 5 km
In Δ ADE, AE = $√{(AD)^2 + (DE)^2}$
= $√{(3)^2 + (4)^2}$ = $√{9 + 16}$ = $√{25}$ = 5 km
Hence, CE = 5 + 5 = 10 km
Question : 4
Riya started from her home to office. She started in east direction. After walking for 4 m she turned to her left and walked 8 m, now she turned left and walked 2 m. After this she turned to right walked 4 m. Now after turning to her right she walked 13 m and reached office. Find the shortest distance between her office and home.
a) $9√41 m$
b) 26 m
c) 87 m
d) $3√41 m$
e) None of these
Answer »Answer: (d)
Question : 5
Maya starts at point T, walks straight towards North to point U which is 4 ft away. She turns left at 90º and walks 1 ft to Q, turns left at 90º and goes to V, who is 1 ft away and once again turns 907deg; right and goes to R, 3 ft away. What is the distance between T and R?
a) 5 ft
b) 8 ft
c) 4 ft
d) 7 ft
Answer »Answer: (a)
The movements of Maya from T to R are as shown in figure.
RT = $√{(RV')^2 +(TV')^2}$ = $√{16 + 9}$ = 5ft
Question : 6
Manish walked 6km facing towards East, then he took a right turn and walked a distance of 9km. he then took a left turn and walked a distance of 6km. How far is he from the starting point?
a) 21km
b) 18km
c) 15 km
d) 15km
e) None of these
Answer »Answer: (c)
GET direction & distance sense test PRACTICE TEST EXERCISES
find directions only
find distance only
find both direction & distance
find directions only section 2
find directions only section 3
find directions only section 4
find directions only section 5
find directions only section 6
find distance only section 2
find distance only section 3
find distance only section 4
find distance only section 5
find distance only section 6
find both direction & distance section 2
find both direction & distance section 3
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