find distance only section 2 Detailed Explanation And More Example
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The following question based on direction & distance sense test topic of verbal reasoning
(a) 6 kms
(b) 2 kms
(c) 4 kms
(d) 8 kms
The correct answers to the above question in:
Answer: (a)
CB = 6 Km
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Read more type 2 section 2 mcqs Based Verbal Reasoning Questions and Answers
Question : 1
Two persons A and B are at a distance of 10 meters from each other in west-east direction respectively. A starts walking in north and B starts walking south and move 5 meter respectively. Then A and B takes right and left turn respectively and stopped after travelling 5 meter each. Find the distance between both of them
a) $10√5$
b) $10√2$
c) $10√3$
d) $10√7$
e) None of these
Answer »Answer: (b)
Question : 2
From her home facing South West, Kavita walks 15 m and turns Northward and walks 12m. How far was she from her home, which was her starting point ?
a) 9 metres
b) 12 metres
c) 10 metres
d) 15 metres
Answer »Answer: (a)
Required distance
AC = $√{AB^2 - BC^2}$
= $√{15^2 - 12^2}$
= $√{225 - 144}$
= $√{81}$
= 9 km
Question : 3
Ramesh went 20 m to the east, then he turned left and after 15 m turned right and went 25 m and then turned right and went 15 m. How far was Ramesh from the starting point ?
a) 35 m
b) 45 m
c) 60 m
d) 40 m
Answer »Answer: (b)
Required distance
= PT = PQ + QT
= (20 + 25)m = 45 m
Question : 4
A person starts walking in south and after walking 20 meters he took a left turn and walks 30 meter and finally took a right turn and stopped after walking 40 meters. Find the distance between his initial position to final position?
a) $30√5$
b) $40√5$
c) $20√5$
d) $55√5$
e) None of these
Answer »Answer: (a)
distance = $60^2 + 30^2 = √(4500) = 30√5$
Question : 5
A postman was returning to the post office which was in front of him to the north. When the post office was 100 metres away from him, he turned to the left and moved 50 metres to deliver the last letter at Shantivilla. He then moved in the same direction for 40 metres, turned to his right and moved 100 metres. How many metres was he away from the post office ?
a) 150
b) 90
c) 0
d) 100
e) None of these
Answer »Answer: (b)
Clearly, the route of the postman is as shown.
So, at the final point the distnace of postman from the post office
= EA = BD
= BC + CD
= (50 + 40) = 90m.
Question : 6
John’s house is 100 metres North of his uncle’s office. His uncle’s house is located 200 metres West of his (uncle’s) office. Kabir is the friend of John and he stays 100 metres East of John’s house. The office of Kabir is located 100 metres South of his house. Then how far is his uncle’s house from Kabir’s office?
a) 300 metres
b) 500 metres
c) 200 metres
d) 400 metres
Answer »Answer: (a)
Required distance
= (200 + 100) metres
= 300 metres
GET direction & distance sense test PRACTICE TEST EXERCISES
find directions only
find distance only
find both direction & distance
find directions only section 2
find directions only section 3
find directions only section 4
find directions only section 5
find directions only section 6
find distance only section 2
find distance only section 3
find distance only section 4
find distance only section 5
find distance only section 6
find both direction & distance section 2
find both direction & distance section 3
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