Arithmetical Reasoning section 1 MCQ Detailed Explanation And More Example
MOST IMPORTANT verbal reasoning - 2 EXERCISES
The following question based on Arithmetical Reasoning topic of verbal reasoning
(a) 42
(b) 18
(c) 22
(d) 43
The correct answers to the above question in:
Answer: (d)
Numbers from 1 to 60, which are divisible by 6 are : 6, 12, 18, 24, 30, 36, 42, 48, 54, 60.
There are 10 such numbers.
Numbers from 1 to 60, the sum of whose digits is 6 are 6, 15, 24, 33, 42, 51, 60.
There are 7 such numbers of which 4 are common to the above ones. So, there are 3 such uncommon numbers.
Numbers from 1 to 60, which have 6 as one of the digits are 6, 16, 26, 36, 46, 56, 60.
Clearly, there are 4 such uncommon numbers.
So, numbers 'not connected with 6'
= 60 – (10 + 3 + 4) = 43.
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Read more question and answers set 1 Based Verbal Reasoning Questions and Answers
Question : 1
A girl counted in the following way on the fingers of her left hand : She started by calling the thumb 1, the index finger 2, middle finger 3, ring finger 4, little finger 5 and then reversed direction calling the ring finger 6, middle finger 7 and so on. She counted upto 1994. She ended counting on which finger?
a) Middle finger
b) Thumb
c) Index finger
d) Ring finger
Answer »Answer: (c)
Clearly, while counting, the numbers associated to the thumb will be : 1, 9,17, 25,.....
i.e. numbers of the form (8n + 1).
Since 1994 = 249 × 8 + 2, so 1993 shall correspond to the thumb and 1994 to the index finger.
Question : 2
Between two book-ends in your study are displayed your five favourite puzzle books. If you decide to arrange the five books in every possible combination and moved just one book every minute, how long would it take you?
a) 3 hours
b) 1 hour
c) 2 hours
d) 4 hours
Answer »Answer: (c)
Clearly, number of ways of arranging 5 books = 5!
= 5 × 4 × 3 × 2 × 1 = 120
So, total time taken = 120 minutes = 2 hours.
Question : 3
Five bells begin to toll together and toll respectively at intervals of 6, 5, 7, 10 and 12 seconds. How many times will they toll together in one hour excluding the one at the start ?
a) 9 times
b) 7 times
c) 8 times
d) 11 times
Answer »Answer: (c)
L.C.M. of 6, 5, 7, 10 and 12 is 420.
So, the bells will toll together after every 420 seconds i.e. 7 minutes.
Now, 7 × 8 = 56 and 7 × 9 = 63.
Thus, in 1-hour (or 60 minutes), the bells will toll together 8 times, excluding the one at the start.
Question : 4
Mac has £ 3 more than Ken, but then Ken wins on the horses and trebles his money, so that he now has £ 2 more than the original amount of money that the two boys had between them. How much money did Mac and Ken have between them before Ken's win ?
a) £ 13
b) £ 9
c) £ 11
d) £ 15
Answer »Answer: (a)
Let money with Ken = x. Then, money with Mac = x + £ 3.
Now, 3x = (x x + £ 3) + £ 2 ⇔ x = £ 5.
Therefore total money with Mac and Ken = 2x + £ 3 = £ 13.
Question : 5
A player holds 13 cards of four suits, of which seven are black and six are red. There are twice as many diamonds as spades and twice as many hearts as diamonds. How many clubs does he holds?
a) 6
b) 4
c) 5
d) 7
Answer »Answer: (a)
Clearly, the black cards are either clubs or spades while the red cards are either diamonds or hearts.
Let the number of spades be x. Then, number of cubes = (7 – x).
Number of diamonds = 2 x number of spades = 2x
Number of hearts = 2 x number of diamonds = 4x
Total number of cards = x + 2x + 4x + 7 – x = 6x + 7.
Therefore 6x + 7 = 13 ⇔ 6x = 6 ⇔ x – 1.
Hence, number of clubs = (7 – x) = 6.
Question : 6
A monkey climbs 30 feet at the beginning of each hour and rests for a while when he slips back 20 feet before he again starts climbing in the beginning of the next hour. If he begins his ascent at 8.00 a.m., at what will he first touch a flag at 120 feet from the ground?
a) 6 p.m.
b) 4 p.m
c) 5 p.m.
d) 8 p.m.
Answer »Answer: (a)
Let ascent of the monkey in 1 hour = ( 30 – 20 ) = 10 feet.
So, the monkey ascends 90 feet in 9 hours i.e., 5 p.m.
Clearly, in the next 1 hour i.e., till 6 p.m.
The monkey ascends remaining 30 feet to touch the flag.
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