Arithmetical Reasoning section 1 MCQ Detailed Explanation And More Example
MOST IMPORTANT verbal reasoning - 2 EXERCISES
The following question based on Arithmetical Reasoning topic of verbal reasoning
(a) Chander
(b) Alok
(c) Bhupesh
(d) Dinesh
The correct answers to the above question in:
Answer: (b)
a + b + c + d = 100
Also, a + b = c + d = 50
c = $d/2, ∴ d/2 + d$ = 50 ⇒ d = 33.3
∴ d > c
Also, a > b & between a and d, a = d + 5
∴ a > d
∴ Alok (b) has the maximum money.
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Read more question and answers set 1 Based Verbal Reasoning Questions and Answers
Question : 1
A group of 1200 persons consisting of captains and soldiers is travelling in a train. For every 15 soldiers there is one captain. The number of captains in the group is ?
a) 80
b) 70
c) 75
d) 85
Answer »Answer: (c)
Generally we may commit mistake of dividing 1200/15. But out of 16 persons there is one captain. so, it will be 1200/16 = 75
Question : 2
A monkey climbs 30 feet at the beginning of each hour and rests for a while when he slips back 20 feet before he again starts climbing in the beginning of the next hour. If he begins his ascent at 8.00 a.m., at what will he first touch a flag at 120 feet from the ground?
a) 6 p.m.
b) 4 p.m
c) 5 p.m.
d) 8 p.m.
Answer »Answer: (a)
Let ascent of the monkey in 1 hour = ( 30 – 20 ) = 10 feet.
So, the monkey ascends 90 feet in 9 hours i.e., 5 p.m.
Clearly, in the next 1 hour i.e., till 6 p.m.
The monkey ascends remaining 30 feet to touch the flag.
Question : 3
A player holds 13 cards of four suits, of which seven are black and six are red. There are twice as many diamonds as spades and twice as many hearts as diamonds. How many clubs does he holds?
a) 6
b) 4
c) 5
d) 7
Answer »Answer: (a)
Clearly, the black cards are either clubs or spades while the red cards are either diamonds or hearts.
Let the number of spades be x. Then, number of cubes = (7 – x).
Number of diamonds = 2 x number of spades = 2x
Number of hearts = 2 x number of diamonds = 4x
Total number of cards = x + 2x + 4x + 7 – x = 6x + 7.
Therefore 6x + 7 = 13 ⇔ 6x = 6 ⇔ x – 1.
Hence, number of clubs = (7 – x) = 6.
Question : 4
Four children A, B, C and D are having some chocolates each. A gives B as many as he already has, he gives C twice of what C already has and he gives D thrice of what D already has. Now, D gives 1/8th of his own chocolates to B. Then A gives 10% chocolates he now owns to C and 20% to B. Finally, all of them have 35 chocolates each. What is the original number of chocolates each had in the beginning ?
a) A-70, B-25, C-25, D-20
b) A -110, B-10, C-10, D-10
c) A-90, B-20, C-20, D-10
d) A-125, B-5, C-5, D-5
Answer »Answer: (b)
Work with options we find that option (b) is correct.
Option (b) | A | B | C | D |
Beginning | 110 | 10 | 10 | 10 |
A gave | 110 - 60 = 50 | 10 + 10 = 20 | 10 + 20 = 30 | 10 + 30 = 40 |
D gave | 20 + 5 = 25 | 40 - 5 = 35 | ||
A gave | 50 - 15 = 35 | 25 + 10 = 35 | 30 + 5 = 35 |
Question : 5
Jaideep was given some money by his mother on his birthday. Jaideep spent all of it in five stores. In each store he spent one rupee more than half of what he had when he came in. How much did he get from his mother?
a) Rs.46
b) Rs.25
c) Rs.30
d) Rs.52
Answer »Answer: (c)
Question : 6
The 30 members of a club decided to play a badminton singles tournament. Every time a member loses a game he is out of the tournament. There are no ties. What is the minimum number of matches that must be played to determine the winner ?
a) 61
b) 15
c) 29
d) None of these
Answer »Answer: (c)
Clearly, every member except one (i.e. the winner) must lose one game to decide the winner. Thus, minimum number of matches to be played = 30 – 1 = 29.
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