Arithmetical Reasoning section 1 MCQ Detailed Explanation And More Example
MOST IMPORTANT verbal reasoning - 2 EXERCISES
The following question based on Arithmetical Reasoning topic of verbal reasoning
(a) 61
(b) 15
(c) 29
(d) None of these
The correct answers to the above question in:
Answer: (c)
Clearly, every member except one (i.e. the winner) must lose one game to decide the winner. Thus, minimum number of matches to be played = 30 – 1 = 29.
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Read more question and answers set 1 Based Verbal Reasoning Questions and Answers
Question : 1
Jaideep was given some money by his mother on his birthday. Jaideep spent all of it in five stores. In each store he spent one rupee more than half of what he had when he came in. How much did he get from his mother?
a) Rs.46
b) Rs.25
c) Rs.30
d) Rs.52
Answer »Answer: (c)
Question : 2
Four children A, B, C and D are having some chocolates each. A gives B as many as he already has, he gives C twice of what C already has and he gives D thrice of what D already has. Now, D gives 1/8th of his own chocolates to B. Then A gives 10% chocolates he now owns to C and 20% to B. Finally, all of them have 35 chocolates each. What is the original number of chocolates each had in the beginning ?
a) A-70, B-25, C-25, D-20
b) A -110, B-10, C-10, D-10
c) A-90, B-20, C-20, D-10
d) A-125, B-5, C-5, D-5
Answer »Answer: (b)
Work with options we find that option (b) is correct.
Option (b) | A | B | C | D |
Beginning | 110 | 10 | 10 | 10 |
A gave | 110 - 60 = 50 | 10 + 10 = 20 | 10 + 20 = 30 | 10 + 30 = 40 |
D gave | 20 + 5 = 25 | 40 - 5 = 35 | ||
A gave | 50 - 15 = 35 | 25 + 10 = 35 | 30 + 5 = 35 |
Question : 3
Four persons, Alok, Bhupesh, Chander and Dinesh have a total of ` 100 among themselves. Alok and Bhupesh between them have as much money as Chander and Dinesh between them, but Alok has more money than Bhupesh; and Chander has only half the money that Dinesh has. Alok has in fact ` 5 more than Dinesh has. Who has the maximum amount of money ?
a) Chander
b) Alok
c) Bhupesh
d) Dinesh
Answer »Answer: (b)
a + b + c + d = 100
Also, a + b = c + d = 50
c = $d/2, ∴ d/2 + d$ = 50 ⇒ d = 33.3
∴ d > c
Also, a > b & between a and d, a = d + 5
∴ a > d
∴ Alok (b) has the maximum money.
GET Arithmetical Reasoning PRACTICE TEST EXERCISES
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