find distance only Detailed Explanation And More Example
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Directions :
Study the information given below carefully and answer the questions given below: A, B, C, D, E, F, G, H and I are nine houses. C is 2 km east of B. A is 1 km north of B and H is 2 km South of A. G is 1 km west of H while D is 3 km east of G and F is 2 km north of G. I is situated just in middle of B and C while E is just in middle of H and D.The following question based on direction & distance sense test topic of verbal reasoning
(a) 1 km
(b) 2 km
(c) 3 km
(d) 4 km
The correct answers to the above question in:
Answer: (a)
I lies in middle of B and C.
So, BI = IC. But bC = 2 km.
Then, BI = IC = 1 km.
I lies directly above E.
Therefore, Required distance = EI = HB = 1 km.
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Read more finding distance sense test Based Verbal Reasoning Questions and Answers
Question : 1
Distance between A and F is
a) 1 km
b) 1.41 km
c) 2 km
d) 3 km
Answer »Answer: (a)
Since GF = AH = 2 km, so F and A lie in the same line.
Therefore, Required distance = AF = GH = 1 km.
Directions :
Study the information given below carefully and answer the questions that follow: On a playing ground, Dinesh, Kunal, Nitin, Atul and Prashant are standing as described below facing the North.- (i) Kunal is 40 metres to the right of Atul.(ii) Dinesh is 60 metres to the south of Kunal.(iii) Nitin is 25 metres to the west of Atul.(iv) Prashant is 90 metres to the north of Dinesh.
Question : 2
If a boy walks from Nitin, meets Atul followed by Kunal, Dinesh and then Prashant, how many metres has he walked if he has travelled the straight distance all through?
a) 155 metres
b) 185 metres
c) 215 metres
d) 245 metres
e) None of these
Answer »Answer: (c)
Required distance = NA + AK + KD + DP
= (25 + 40 + 60 + 90) m = 215 m.
Question : 3
My friend and I started simultaneously towards each other from two places 100 m apart. After walking 30 m, my friend turns left and goes 10m, then he turns right and goes 20 m and then turns right again and comes back to the road on which he had started walking. If we walk with the same speed, what is the distance between us at this point of time ?
a) 20 m
b) 40 m
c) 50 m
d) 30 m
Answer »Answer: (a)
Friend covers a total distance of
= (30 + 10 + 20 + 10) = 70 m
Distance between them
= 70 – 50 = 20 m
Question : 4
Distance between E and G is
a) 1 km
b) 1.5 km
c) 2 km
d) 5 km
Answer »Answer: (c)
Since E lies in middle of H and D, so HE = ED. But HD = 2 km.
So, HE = ED = 1 km.
Therefore, Required distance = GE = GH + HE
= (1 + 1) km = 2 km.
Question : 5
X and Y start moving towards each other from two places 200 m apart. After walking 60 m, Y turns left and goes 20 m, then he turns right and goes 40 m. He then turns right again and comes back to the road on which he had started walking. If X and Y walk with the same speed, what is the distance between then now?
a) 20 m
b) 30 m
c) 40 m
d) 50 m
Answer »Answer: (c)
Clearly, Y moves 60 m from Q up to A, then 20 m up to B, 40 m up to C and then up to D.
So, AD = BC = 40 m. QD = (60 + 40) m = 100 m.
Since X and Y travel in the same time i.e. (60 + 20 + 40 + 20) m = 140 m.
So, X travels 140 m up to A.
Therefore, Distance between X and Y = AD = (100 - 60) m = 40 m.
Question : 6
Two houses start from the opposite points of a main road, 150 km apart. The first bus runs for 25 km and takes a right turn and then runs for 14 km. It then turns left and runs for another 25 km and takes the direction back to reach the main road. In the meantime, due to a minor breakdown, the other bus has run only 35 km along the main road. What would be the distance between the two buses at this point?
a) 65 km
b) 75 km
c) 80 km
d) 85 km
e) 90 km
Answer »Answer: (a)
Let X and Y be two buses. Bus X travels along the path PA, AB, BC, CD
Now, AD = BC = 25 km. So, PD = PA + AD = 50 km. Bus Y travels 35 km up to E.
Therefore, Distance between two buses = PQ - (PD + QE)
= [150 - (50 + 35)] km = 65 km.
GET direction & distance sense test PRACTICE TEST EXERCISES
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