find distance only Detailed Explanation And More Example

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The following question based on direction & distance sense test topic of verbal reasoning

Questions : Two houses start from the opposite points of a main road, 150 km apart. The first bus runs for 25 km and takes a right turn and then runs for 14 km. It then turns left and runs for another 25 km and takes the direction back to reach the main road. In the meantime, due to a minor breakdown, the other bus has run only 35 km along the main road. What would be the distance between the two buses at this point?

(a) 65 km

(b) 75 km

(c) 80 km

(d) 85 km

e) 90 km

The correct answers to the above question in:

Answer: (a)

Let X and Y be two buses. Bus X travels along the path PA, AB, BC, CD

Now, AD = BC = 25 km. So, PD = PA + AD = 50 km. Bus Y travels 35 km up to E.

Therefore, Distance between two buses = PQ - (PD + QE)

= [150 - (50 + 35)] km = 65 km.

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Read more finding distance sense test Based Verbal Reasoning Questions and Answers

Question : 1

X and Y start moving towards each other from two places 200 m apart. After walking 60 m, Y turns left and goes 20 m, then he turns right and goes 40 m. He then turns right again and comes back to the road on which he had started walking. If X and Y walk with the same speed, what is the distance between then now?

a) 20 m

b) 30 m

c) 40 m

d) 50 m

Answer: (c)

Clearly, Y moves 60 m from Q up to A, then 20 m up to B, 40 m up to C and then up to D.

So, AD = BC = 40 m. QD = (60 + 40) m = 100 m.

Since X and Y travel in the same time i.e. (60 + 20 + 40 + 20) m = 140 m.

So, X travels 140 m up to A.

Therefore, Distance between X and Y = AD = (100 - 60) m = 40 m.

Directions :
Study the information given below carefully and answer the questions given below: A, B, C, D, E, F, G, H and I are nine houses. C is 2 km east of B. A is 1 km north of B and H is 2 km South of A. G is 1 km west of H while D is 3 km east of G and F is 2 km north of G. I is situated just in middle of B and C while E is just in middle of H and D.

[M.A.T. 2003]

Question : 2

Distance between E and G is

a) 1 km

b) 1.5 km

c) 2 km

d) 5 km

Answer: (c)

Since E lies in middle of H and D, so HE = ED. But HD = 2 km.

So, HE = ED = 1 km.

Therefore, Required distance = GE = GH + HE

= (1 + 1) km = 2 km.

Question : 3

Distance between E and I is

a) 1 km

b) 2 km

c) 3 km

d) 4 km

Answer: (a)

I lies in middle of B and C.

So, BI = IC. But bC = 2 km.

Then, BI = IC = 1 km.

I lies directly above E.

Therefore, Required distance = EI = HB = 1 km.

Question : 4

Raj travelled from a point X straight to Y at a distance of 80 metres. He turned right and walked 50 metres, then again turned right and walked 70 metres. Finally, he turned right and walked 50 metres. How far is he from the starting point?

a) 10 metres

b) 20 metres

c) 50 metres

d) 70 metres

e) 90 metres

Answer: (a)

The movements of Raj are as shown in Fig . 30.

(X to Y, Y to A, A to B, B to C).

Therefore, Raj's distance from the starting point = XC = (XY - YC)

= (XY - BA)

= (80 - 70) m = 10 m.

Question : 5

A man walks 30 metres towards South. Then, turning to his right, he walks 30 metres. Then, turning to his left, he walks 20 metres. Again, he turns to his left and walks 30 metres. How far is he from his initial position?

a) 20 metres

b) 30 metres

c) 50 metres

d) 60 metres

e) 80 metres

Answer: (c)

The movements of the man are as shown in Fig. 25.

Therefore, Man's distance from initial position A.

= AE = (AB + BE) = (AB + CD)

= (30 + 20) m = 50 m.

Question : 6

A man leaves for his office from his house. He walks towards East. After moving a distance of 20 m, he turns South and walks 10 m. Then he walks 35 m towards the West and further 5 m towards the North. He then turns towards East and walks 15 m. What is the straight distance (in metres) between his initial and final positions?

a) 0

b) 5

c) 15

d) Cannot be determined

e) None of these

Answer: (b)

The movements of the man from A to F are as shown in Fig. 13

Clearly, DC = AB + EF. Therefore, F in line with A.

Also, AF = (BC - DE) = 5 m.

So, the man is 5 metres away from his initial position.

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