find distance only Detailed Explanation And More Example
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The following question based on direction & distance sense test topic of verbal reasoning
(a) 0
(b) 5
(c) 15
(d) Cannot be determined
e) None of these
The correct answers to the above question in:
Answer: (b)
The movements of the man from A to F are as shown in Fig. 13
Clearly, DC = AB + EF. Therefore, F in line with A.
Also, AF = (BC - DE) = 5 m.
So, the man is 5 metres away from his initial position.
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Read more finding distance sense test Based Verbal Reasoning Questions and Answers
Question : 1
A man walks 30 metres towards South. Then, turning to his right, he walks 30 metres. Then, turning to his left, he walks 20 metres. Again, he turns to his left and walks 30 metres. How far is he from his initial position?
a) 20 metres
b) 30 metres
c) 50 metres
d) 60 metres
e) 80 metres
Answer »Answer: (c)
The movements of the man are as shown in Fig. 25.
Therefore, Man's distance from initial position A.
= AE = (AB + BE) = (AB + CD)
= (30 + 20) m = 50 m.
Question : 2
Raj travelled from a point X straight to Y at a distance of 80 metres. He turned right and walked 50 metres, then again turned right and walked 70 metres. Finally, he turned right and walked 50 metres. How far is he from the starting point?
a) 10 metres
b) 20 metres
c) 50 metres
d) 70 metres
e) 90 metres
Answer »Answer: (a)
The movements of Raj are as shown in Fig . 30.
(X to Y, Y to A, A to B, B to C).
Therefore, Raj's distance from the starting point = XC = (XY - YC)
= (XY - BA)
= (80 - 70) m = 10 m.
Question : 3
Two houses start from the opposite points of a main road, 150 km apart. The first bus runs for 25 km and takes a right turn and then runs for 14 km. It then turns left and runs for another 25 km and takes the direction back to reach the main road. In the meantime, due to a minor breakdown, the other bus has run only 35 km along the main road. What would be the distance between the two buses at this point?
a) 65 km
b) 75 km
c) 80 km
d) 85 km
e) 90 km
Answer »Answer: (a)
Let X and Y be two buses. Bus X travels along the path PA, AB, BC, CD
Now, AD = BC = 25 km. So, PD = PA + AD = 50 km. Bus Y travels 35 km up to E.
Therefore, Distance between two buses = PQ - (PD + QE)
= [150 - (50 + 35)] km = 65 km.
Question : 4
A boy rode his bicycle northwards, then turned left and rode one km and again turned left and rode 2 km. He found himself exactly one km west of his starting point. How far did he ride northwards initially?
a) 1 km
b) 2 km
c) 5 km
d) 8 km
e) 10 km
Answer »Answer: (b)
Clearly, the boy rode from A to B, then to C and finally up to D.
Since D lies to the west of A, so required distance = AB = CD = 2 km.
Question : 5
A and B both are walking away from point 'X'. A walked 3 m and B walked 4 m from it, then A walked 4 m North of X and B walked 5 m south of A. What is the distance between them now?
a) 9.5 m
b) 9 m
c) 16 m
d) 11.40 m
e) 10.40 m
Answer »Answer: (d)
Required distance, AB = $√{(72 + 92)}$ = $√{130}$ = 11.40 m
Question : 6
Ram goes 15 m North, then turns right and walks 20 m, then again turns right and walks 10 m, then again turns right and walks 20 m. How far is he from his original position?
a) 5
b) 10
c) 15
d) 20
e) 25
Answer »Answer: (a)
DC = EB = 5 m
Therefore, Required distance = AE = AB + BE
= 10 + 5 m = 15 m.
GET direction & distance sense test PRACTICE TEST EXERCISES
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