find distance only Detailed Explanation And More Example

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The following question based on direction & distance sense test topic of verbal reasoning

Questions : Shyam walks 6 m towards East, then turns right and walks 9 m. Again, he turns to his left and walks 6 m. At what distance is he now from his original point?

(a) 15 m

(b) 21 m

(c) 18 m

(d) Cannot be determined

e) None of these

The correct answers to the above question in:

Answer: (a)

According to the question, the direction diagram is as follows. O is the mid - point of BC and

AD OB = OC = $9/2$ = 4.5 m

OA = $√{(AB)^2 + (OB)^2}= √{(6)^2+ (4.5)^2}$

= $√{(36 + 20.25)} = √{(56.25)}$ = 7.5 m

OD = OA = 7.5

Therefore, Required distance, AD = AO + OD = 7.5 + 7.5 = 15 m.

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Read more finding distance sense test Based Verbal Reasoning Questions and Answers

Question : 1

A man goes 5 km East from his office. He then takes left turn and walks 3 km. He again takes left turn and walks 5 km. How far is he starting point?

a) 3 km

b) 4 km

c) 6 km

d) 7 km

e) 8 km

Answer: (a)

According to the question, the direction diagram is as follows.

OB = CD = 5 km BC = OD = 3 km Therefore, Required distance, OD = 3 km.

Question : 2

John travels 14 km westwards and then turns left and travels 6 km and further turns left and travels 26 km. How far is John now from the starting point?

a) $√180$ km

b) $√80$ km

c) $√100$ km

d) None of these

Answer: (a)

According to the question, the direction diagram will be as follows.

AB = CE = 14 km

BC = AE = 6 km

CD = 26 km

ED = CD - CE = 26 - 14 = 12 km

Therefore, Required distance, AD = $√{(AE)^2 + (ED)^2}$ (by pythagoras theorem)

= $√{(62 + 122)}$ = $√180$ km

Question : 3

Hari travelled 17 km to the East, he turned left and went 15 km, he again turned left and went 17 km. How far is he from the starting point?

a) 32 km

b) 17 km

c) 2 km

d) 15 km

Answer: (d)

According to the questions, the direction diagram will be as follows.

Now, AB = CD = 17 km and BC = AD = 15 km

Therefore, Required distance, AD = 15 km.

Question : 4

Amol travels a distance of 10 ft from A to B. Then, he turns to left and travels 5 ft and again turns to left and travels 2 ft. Finally, he turns to left and moves 5 ft. How far is he now from his original position?

a) 5 ft

b) 6 ft

c) 8 ft

d) 12 ft

e) 10 ft

Answer: (b)

According to the question, the direction diagram is as follows. A = Original position,

E = Final position AB = 10 ft, BC = DE = 5 ft CD = EB = 2 ft

Therefore, Required distance, AE = AB - EB = 10 -2 = 8 ft.

Question : 5

Molly travelled from point A to point B which is 5 ft. He, then travelled 6 ft to his right and then turned to left and went 4 ft. Finally, he again went 6 ft to his left. How far is he from the point B now?

a) 4 ft

b) 10 ft

c) 6 ft

d) 5 ft

Answer: (a)

According to the question, the direction diagram will be as follows. Therefore, Required distance, BE = 4 ft.

Question : 6

Ankit started walking towards North. After walking 30 m, he turned towards left and walked 40 m. He, then turned left and walked 30 m. He again turned left and walked 50 m. How far is the from his original position?

a) 40 m

b) 50 m

c) 30 m

d) 10 m

e) 12 m

Answer: (d)

According to the question, the direction diagram will be as follows. Therefore, Required distance, PT = ST - SP = 50 - 40 = 10 m.

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