find distance only Detailed Explanation And More Example

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The following question based on direction & distance sense test topic of verbal reasoning

Questions : In the given figure. P is 300 km eastward of O and Q is 400 km north of O. R is exactly in the middle of Q and P. The distance between Q and R is

(a) 300 km

(b) 250 km

(c) 250 km

(d) 350 km

The correct answers to the above question in:

Answer: (c)

Clearly, PQ = $√{OP^2 + OQ^2}$

= $√{90000 + 160000}$ = 500km

Since, R is the midpoint of PQ, 

So QR = $1/2$ X PQ

= 250 km

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Read more finding distance sense test Based Verbal Reasoning Questions and Answers

Question : 1

A girl walks 30 metre towards south, then turning to her right she walks 30 metre, then turning to her left, she walks 20 metre, again she turns to her left and walks 30 metre. How far is she from her initial position?

a) 30 metre

b) 60 metre

c) 20 metre

d) 50 metre

Answer: (d)

direction-and-distance-verbal-reasoning

Required distance = AE

= (30 + 20) metres

= 50 metres

Question : 2

A child is looking for his father. He went 90 metres in the East before turning to his right. He went 20 metres before turning to his right again to look for his father at his uncle's place 30 metres from this point. His father was not there. From here he went 100 metres to the North before meeting his father in a street How far did the son meet his father from the starting point ?

a) 140 metres

b) 100 metres

c) 80 metres

d) 260 metres

Answer: (b)

direction-and-distance-verbal-reasoning

The movements of the child from A to E are as shown in the figure,

Clearly, the child meeta his father at E.

Now, AF = (AB - FB)

= (AB - DC) = (90 - 30)m = 60m.

EF = (DE - DF) = (DE - BC)

= (100 - 20) = 80m.

Question : 3

Leela starts from a point and walks 1 km east and then turns left and walks 2 km and turns right and walks 2 km again. She starts towards a point 2 km towards her right, from where again she walks 1 km left. How far is she from the starting point?

a) 4 km

b) 2 km

c) 3 km

d) 5 km

Answer: (a)

direction-and-distance-verbal-reasoning

Required distance

= AB + BE + EF

= (1 + 2 + 1) km = 4 km

Question : 4

A man walks 1 km towards East and then he turns to South and walks 5 km. Again he turns to East and walks 2 km, after this he turns to North and walks 9 km. Now, how far is he from his starting point?

a) 4 km

b) 7 km

c) 3 km

d) 5 km

Answer: (d)

direction-and-distance

The movements of the man are as shown in Fig.

(A to B, B to C, C to D and D to E)

Clearly, DF = BC = 5 km

EF= (DE- DF) = (9-5) km = 4 km

BF = CD = 2 km

AF = AB + BF = AB + CD = (1 + 2) km = 3 km

∴ Man's distance from starting point A = AE

= $√{AF^2 + EF^2}$ = $√{3^2 + 4^2}$ = $√{25}$ = 5 km

Question : 5

Ram walks 3 km towards East and takes a left turn and walks for one km before he turns left and walks 2 km to take another left turn to walk for another one km. How many km is he away from his starting point?

a) 2kms

b) 4kms

c) 1km

d) 3kms

Answer: (c)

direction-and-distance-verbal-reasoning

Question : 6

Rimpy, on her morning walk, starting from home she walks to the North for 250 m, then she turns to her right and travels 20 m and then she again turns to the right and drives straight another 250 m. How much distance has she now to cover to go back to her home?

a) 4 m

b) 25 m

c) 20 m

d) 40 m

e) 30 m

Answer: (c)

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