find distance only Detailed Explanation And More Example

MOST IMPORTANT verbal reasoning - 15 EXERCISES

Top 10,000+ Verbal Memory Based Exercises

The following question based on direction & distance sense test topic of verbal reasoning

Questions : Rimpy, on her morning walk, starting from home she walks to the North for 250 m, then she turns to her right and travels 20 m and then she again turns to the right and drives straight another 250 m. How much distance has she now to cover to go back to her home?

(a) 4 m

(b) 25 m

(c) 20 m

(d) 40 m

e) 30 m

The correct answers to the above question in:

Answer: (c)

Practice direction & distance sense test (find distance only) Online Quiz

Discuss Form

Valid first name is required.
Please enter a valid email address.
Your genuine comment will be useful for all users! Each and every comment will be uploaded to the question after approval.

Read more finding distance sense test Based Verbal Reasoning Questions and Answers

Question : 1

Ram walks 3 km towards East and takes a left turn and walks for one km before he turns left and walks 2 km to take another left turn to walk for another one km. How many km is he away from his starting point?

a) 2kms

b) 4kms

c) 1km

d) 3kms

Answer: (c)

direction-and-distance-verbal-reasoning

Question : 2

A man walks 1 km towards East and then he turns to South and walks 5 km. Again he turns to East and walks 2 km, after this he turns to North and walks 9 km. Now, how far is he from his starting point?

a) 4 km

b) 7 km

c) 3 km

d) 5 km

Answer: (d)

direction-and-distance

The movements of the man are as shown in Fig.

(A to B, B to C, C to D and D to E)

Clearly, DF = BC = 5 km

EF= (DE- DF) = (9-5) km = 4 km

BF = CD = 2 km

AF = AB + BF = AB + CD = (1 + 2) km = 3 km

∴ Man's distance from starting point A = AE

= $√{AF^2 + EF^2}$ = $√{3^2 + 4^2}$ = $√{25}$ = 5 km

Question : 3

In the given figure. P is 300 km eastward of O and Q is 400 km north of O. R is exactly in the middle of Q and P. The distance between Q and R is

a) 300 km

b) 250 km

c) 250 km

d) 350 km

Answer: (c)

Clearly, PQ = $√{OP^2 + OQ^2}$

= $√{90000 + 160000}$ = 500km

Since, R is the midpoint of PQ, 

So QR = $1/2$ X PQ

= 250 km

Question : 4

A child is looking for his father. He went 90 metres in the east before turning to his right. He went 20 metres before turning to his right again to look for his father at his uncle’s place 30 metres from this point. His father was not there. From here he went 100 metres to his north before meeting his father in a street. How far did the son meet his father from the starting point?

a) 100 m

b) 140 m

c) 80 m

d) 260 m

Answer: (a)

direction-and-distance-verbal-reasoning

Required distance = AF

= $√{80^2 + 60^2}$

 = $√{6400 + 3600}$

= $√{10000}$ = 100 km

Question : 5

Namita walks 14 metres towards west, then turns to her right and walks 14 metres and then turns to her left and walks 10 metres. Again turning to her left she walks 14 metres. What is the shortest distance (in metres) between her starting point and the present position?

a) 24

b) 38

c) 10

d) 28

Answer: (a)

direction-and-distance

The movements of Namita are shown in figure

(A to B, B to C, C to D and D to E).

Clearly, Namita’s distance from his initial position

= AE = (AB + BE) = (AB + CD) = (14 + 10) m

= 24 m.

Question : 6

X and Y start moving towards each other from two places 200 m apart. After walking 60 m, B turns left and goes 20 m, then he turns right and goes 40 m. He then turns right again and comes back to the road on which he had started walking. If A and B walk with the same speed, what is the distance between them now ?

a) 40 m

b) 30 m

c) 20 m

d) 50 m

Answer: (a)

direction-and-distance-verbal-reasoning

Clearly Y moves 60m from Q upto A, then 20m upto b, 40m upto c and then upto D.

So, AD = BC = 40m.

QD = (60 + 40)m = 100m.

Since A and B travel with the same speed, A will travel the same speed along the horizontal as B travels in the same time.

i.e. (60 + 20 + 40+ 20) = 140m

So, X travels 140 m upto A.

∴ Distance between X and Y = AD

= (100 - 60)m = 40m.

Recently Added Subject & Categories For All Competitive Exams

100+ Quadratic Equation Questions Answers PDF for Bank

Quadratic Equation multiple choice questions with detailed answers for IBPS RRB SO. more than 250 Attitude practice test exercises for all competitive exams

03-Jul-2024 by Careericons

Continue Reading »

IBPS Aptitude Linear Equations MCQ Questions Answers PDF

Linear equations multiple choice questions with detailed answers for IBPS RRB SO. more than 250 Attitude practice test exercises for all competitive exams

03-Jul-2024 by Careericons

Continue Reading »

New 100+ Compound Interest MCQ with Answers PDF for IBPS

Compound Interest verbal ability questions and answers solutions with PDF for IBPS RRB PO. Aptitude Objective MCQ Practice Exercises all competitive exams

02-Jul-2024 by Careericons

Continue Reading »

100+ Mixture and Alligation MCQ Questions PDF for IBPS

Most importantly Mixture and Alligation multiple choice questions and answers with PDF for IBPS RRB PO. Aptitude MCQ Practice Exercises all Bank Exams

02-Jul-2024 by Careericons

Continue Reading »