find distance only Detailed Explanation And More Example

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The following question based on direction & distance sense test topic of verbal reasoning

Questions : Prabhu travelled from his house a distance of 20 kms to his friend’s house. After some time he left his friends house and took a turn towards right and travelled 15 kms to reach a park. After resting for a while, he again started and turned to right and travelled 18 kms to reach a petrol pump. From there he again turned right and covered a distance of 15 kms. How many km more he has to travel to reach home?

(a) 18 kms

(b) 23 kms

(c) 2 kms

(d) 21 kms

The correct answers to the above question in:

Answer: (c)

direction-and-distance-verbal-reasoning

AE = 2 km.

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Read more finding distance sense test Based Verbal Reasoning Questions and Answers

Question : 1

I go 5 km. cast then turn right and go 8 km. Then turn left and go 5 km. and then I turn left and I go 8 km. At what distance I am from the starting point?

a) 10 km.

b) 6 km

c) 13 km.

d) 7 km.

Answer: (a)

direction-and-distance-verbal-reasoning

Required Distance

= 5 + 5 = 10 km

Question : 2

I go 5 km East, then turn right and go 8 km. Then I turn left and go 5 km and then I turn left and go 8 km. At what distance am I from the starting point?

a) 0

b) 5

c) 8

d) 10

Answer: (d)

direction-and-distance-verbal-reasoning

AE = (5 + 5) km = 10 km.

Question : 3

X and Y start moving towards each other from two places 200 m apart. After walking 60 m, B turns left and goes 20 m, then he turns right and goes 40 m. He then turns right again and comes back to the road on which he had started walking. If A and B walk with the same speed, what is the distance between them now ?

a) 40 m

b) 30 m

c) 20 m

d) 50 m

Answer: (a)

direction-and-distance-verbal-reasoning

Clearly Y moves 60m from Q upto A, then 20m upto b, 40m upto c and then upto D.

So, AD = BC = 40m.

QD = (60 + 40)m = 100m.

Since A and B travel with the same speed, A will travel the same speed along the horizontal as B travels in the same time.

i.e. (60 + 20 + 40+ 20) = 140m

So, X travels 140 m upto A.

∴ Distance between X and Y = AD

= (100 - 60)m = 40m.

Question : 4

Radha moves towards South-east a distance of 7 km, then she moves towards West and travels a distance of 14 m. From here, she moves towards North-west a distance of 7 m and finally she moves a distance of 4 m towards East and stood at that point. How far is the starting point from where she stood?

a) 4 m

b) 11 m

c) 3 m

d) 10 m

Answer: (d)

direction-and-distance

The movements of Radha are as shown in figure. Clearly, Radha’s distance from the starting point O = OD = (OC – CD) = (AB – CD) = (14 – 4) m = 10 m.

Question : 5

Rama left home and walked 5 km southwards, turned right and walked 2 km and turned right and walked 5 km and turned left and walked 5 km. How many kilometres will she have to walk to reach her home straight?

a) 7

b) 15

c) 5

d) 17

Answer: (a)

direction-and-distance-verbal-reasoning

She will have to traval 7 km to reach her home.

Question : 6

Ram went 20 metres to the north then turned towards east and walked another 5 metres, then he turned towards right and covered 20 metres. How far is he from the starting point?

a) 4 metre

b) 6 metre

c) 3 metre

d) 5 metre

Answer: (d)

direction-and-distance-verbal-reasoning

Clearly, the horizontal distance

= (7 + 15) km = 22 km

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