find distance only Detailed Explanation And More Example

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The following question based on direction & distance sense test topic of verbal reasoning

Questions : Dinesh travels from a point A 8 km towards B eastwards and turns right and walks 12 km to C, turns again right and walks 4 km to a point D, again turns right and travels 8 km to E. From E he turns left and walks to F 4 km. Now how far is he from starting pont?

(a) 6 km

(b) 12 km

(c) 4 km

(d) 8 km

The correct answers to the above question in:

Answer: (c)

direction-and-distance-verbal-reasoning

AF = 4 Km.

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Read more finding distance sense test Based Verbal Reasoning Questions and Answers

Question : 1

Rajesh starting from his house, goes 4 km. in the East, then he turns to his right and goes 3 km. What is his final distance from his house?

a) 5. 5 km

b) 4 km

c) 5km

d) 4.5 km

e) None of these

Answer: (c)

direction-and-distance

Question : 2

From my house I walked 5 km towards North. I turned right and walked 3 km. Againt I went one km to the south. How far am I from my house?

a) 6 km

b) 5 km

c) 7 km

d) 4 km

Answer: (b)

direction-and-distance-verbal-reasoning

Required distance

AD = $√{AE^2 + DE^2}$

= $√{4^2 + 3^2}$

= $√{16+ 9}$

= $√{25}$ = 5 km

Question : 3

I walk 12 km to the North, then 10 kilometres East and then 12 km South. How far am I from the starting point ?

a) 24 km

b) 10 k

c) 34 km

d) 22 km

Answer: (b)

direction-and-distance-verbal-reasoning

Required distance = AD

= 10 km

Question : 4

A and B are standing at place “P”. They start moving in the opposite directions at the speed of 5 kmph and 4 kmph respectively. What will be the distance between them after 3 hours?

a) 21 kms.

b) 27 kms

c) 3 kms.

d) 18 kms.

Answer: (b)

Distance between them after 3 hours

= 3 (5 + 4) km.

= 3 × 9 km. = 27 km.

Question : 5

A man walks 1 km towards East and then he turns to his south and walks 5 km. Again he turns to East and walks 2 km, after this he turns to North and walks 9 km. Now, how far is he from his starting point ?

a) 5 km

b) 3 km

c) 4 km

d) 7 km

e) None of these

Answer: (a)

The movements of the man are as shown in Figure (A to B, B to C, C to D, D to E).

Clearly, DF = BC = 5 km.

EF = (DE – DF) = (9 – 5) km = 4 km

BF = CD = 2 km

AF = AB + BF = AB + CD = (1 + 2) km = 3 km.

Man’s distance from starting point A

$√{AF^2 + EF^2}$ 

= $√{3^2 + 4^2}$ = √25 = 5 km

direction-and-distance

Question : 6

Morning time, Sohan goes towards sun for a distance of 50m. Then he turns right twice and goes straight 40m and 20m respectively. At last he turns once more right and goes straight for the distance of 40m. How far is he now from his starting point ?

a) 30 m

b) 60 m

c) 20 m

d) 50 m

Answer: (a)

direction-and-distance

XD = XA – AD = 50 – 20 = 30m

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