find distance only Detailed Explanation And More Example

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The following question based on direction & distance sense test topic of verbal reasoning

Questions : A man walks 1 km towards East and then he turns to his south and walks 5 km. Again he turns to East and walks 2 km, after this he turns to North and walks 9 km. Now, how far is he from his starting point ?

(a) 5 km

(b) 3 km

(c) 4 km

(d) 7 km

e) None of these

The correct answers to the above question in:

Answer: (a)

The movements of the man are as shown in Figure (A to B, B to C, C to D, D to E).

Clearly, DF = BC = 5 km.

EF = (DE – DF) = (9 – 5) km = 4 km

BF = CD = 2 km

AF = AB + BF = AB + CD = (1 + 2) km = 3 km.

Man’s distance from starting point A

$√{AF^2 + EF^2}$ 

= $√{3^2 + 4^2}$ = √25 = 5 km

direction-and-distance

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Read more finding distance sense test Based Verbal Reasoning Questions and Answers

Question : 1

A and B are standing at place “P”. They start moving in the opposite directions at the speed of 5 kmph and 4 kmph respectively. What will be the distance between them after 3 hours?

a) 21 kms.

b) 27 kms

c) 3 kms.

d) 18 kms.

Answer: (b)

Distance between them after 3 hours

= 3 (5 + 4) km.

= 3 × 9 km. = 27 km.

Question : 2

Dinesh travels from a point A 8 km towards B eastwards and turns right and walks 12 km to C, turns again right and walks 4 km to a point D, again turns right and travels 8 km to E. From E he turns left and walks to F 4 km. Now how far is he from starting pont?

a) 6 km

b) 12 km

c) 4 km

d) 8 km

Answer: (c)

direction-and-distance-verbal-reasoning

AF = 4 Km.

Question : 3

Rajesh starting from his house, goes 4 km. in the East, then he turns to his right and goes 3 km. What is his final distance from his house?

a) 5. 5 km

b) 4 km

c) 5km

d) 4.5 km

e) None of these

Answer: (c)

direction-and-distance

Question : 4

Morning time, Sohan goes towards sun for a distance of 50m. Then he turns right twice and goes straight 40m and 20m respectively. At last he turns once more right and goes straight for the distance of 40m. How far is he now from his starting point ?

a) 30 m

b) 60 m

c) 20 m

d) 50 m

Answer: (a)

direction-and-distance

XD = XA – AD = 50 – 20 = 30m

Question : 5

Deepu started his journey from A and moves 2 km towards South, then he turns right and moves 1 2 kilometre. Again he takes a right turn and walks 2 km. Now he takes a left turn and walks 3 km more. How far he is from the starting point ?

a) 2.5 km

b) 1.5 km

c) 3.5 km

d) 7.5 km

Answer: (c)

direction-and-distance-verbal-reasoning

AE = $(3 + {1}/2)$km

= 3.5 km.

Question : 6

A goes 7 km eastward, then turns right and proceeds 7 km, then travels 15 km towards left, then travels 12 km towards left and finally goes 5 km northward. Calculate his distance from his initial place in the horizontal direction.

a) 22 km.

b) 25 km.

c) 20 km.

d) 23 km.

Answer: (a)

direction-and-distance-verbal-reasoning

Clearly, the horizontal distance

= (7 + 15) km = 22 km

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