find distance only Detailed Explanation And More Example
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The following question based on direction & distance sense test topic of verbal reasoning
(a) 75 kms
(b) 85 kms
(c) 65 kms
(d) 80 kms
The correct answers to the above question in:
Answer: (c)
Let X and Y be two buses.
Bus X travels along the path PA, AB, BC, CD.
Now, AD = BC =25 km
So, PD = PA + AD = 50 km
Bus Y travels 35 km upto E
∴ Distance between two buses = PQ - (PD + QE)
= {150 - (50+35)} = 65 km
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Read more finding distance sense test Based Verbal Reasoning Questions and Answers
Question : 1
Ricky after travelling for 5 km. took right turn and travelled 6 km. before taking left turn and then travelled for 3 km. find his final distance from home.
a) 9 km
b) 10 km
c) 12 km
d) 11 km
e) None of these
Answer »Answer: (b)
Question : 2
Seeta and Ram both start from a point towards North. Seeta turns to left after walking 10 km. Ram turns to right after walking the same distance. Seeta waits for sometime and then walks another 5 km, whereas Ram walks only 3 km. They both then return to their respective South and walk 15 km forward. How far is Seeta from Ram ?
a) 12 km
b) 10 km
c) 8 km
d) 15 km
Answer »Answer: (c)
Required distance EF
= (5 + 3) km
= 8 km
Question : 3
Peter walked 8 kms. west and turned right and walked 3 kms. The again he turned right and walked 12 kms. How far is he from the starting point ?
a) 8
b) 5
c) 7
d) 4
Answer »Answer: (b)
Required distance
AE = $√{AD^2 + DE^2}$
= $√{3^2 + 4^2}$
= $√{9+ 16}$
= $√{25}$ = 5 km
Question : 4
Kishore starts from a point and walks 6 km towards East and turning to his left he moves 3 km. After this, he again turns to his left and moves 6 km. Now, how far is he from his starting point ?
a) 2 km
b) 5 km
c) 3 km
d) 4 km
Answer »Answer: (c)
AD = 3 km
Question : 5
A person starts from a point A and travels 3 km eastwards to B and then turns left and travels thrice that distance to reach C. He again turns left and travels five times the distance he covered between A and B and reaches his destination D. the shortest distance between the starting point and the destination is
a) 15 km
b) 18 km
c) 12 km
d) 16 km
Answer »Answer: (a)
The movements of the person are as shown in the figure.
Clearly, AB = 3 km; BC = 3AB = (3 × 3) km = 9 km;
CD = 5 AB = (5 × 3) km = 15 km.
Draw AE
CD. Then, CE = AB = 3 km and AE = BC = 9 km.
DE = (CD – CE) = (15 – 3) km = 12 km.
In ΔAED, AD2 = AE2 + DE2 ; AD = $√{9^2 + 12^2}$
$√{225}$ = 15 km. So, required distance
= AD = 15 km.
Question : 6
Sohan started from point X and travelled forward 8 km up to point Y, then turned towards right and travelled 5km up to point Z, then turned right and travelled 7km up to point A and then turned towards right and travelled 5km up to B. What is the distance between points B and X?
a) 2 km
b) 4 km
c) 1 km
d) 3 km
Answer »Answer: (c)
Clearly, the route of Sohan is as shown in the diagram given below :
Here, XB = XY – YB = XY – AZ (∴ YB = AZ)
= 8 km – 7 km = 1 km
GET direction & distance sense test PRACTICE TEST EXERCISES
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