find distance only Detailed Explanation And More Example

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The following question based on direction & distance sense test topic of verbal reasoning

Questions : A man drives his car 50 km towards eastward direction. He turned right went for 30 km, then he turned west and drive for 10km. How far is he from the starting point ?

(a) 60 km

(b) 20 km

(c) 50 km

(d) 100 km

The correct answers to the above question in:

Answer: (c)

direction-and-distance-verbal-reasoning

Required distance

AD = $√{AE^2 + DE^2}$

= $√{40^2 + 30^2}$

 = $√{1600 + 900}$

= $√{2500}$ = 50 km

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Read more finding distance sense test Based Verbal Reasoning Questions and Answers

Question : 1

Starting from a point O, Mahesh walks a distance of 5 km. South, then turns to his right and walks 3 km. From there he again turns right and walks 5 km. He then turns to his left and walks 5 km. How far is he from the starting point?

a) 8 km.

b) 15 km

c) 13 km.

d) 5 km.

Answer: (a)

direction-and-distance-verbal-reasoning

Required distance

= OS = OR + RS

= (3 + 5) km = 8 km.

Question : 2

Ram and Shyam started walking in opposite directions from a point. Ram covered 7 km and Shyam covered 5km. Ram turned right and walked 3 km. Shyam turned left and walked 3km. How far are they from each other?

a) 10 km

b) 14 km

c) 8 km

d) 12 km

Answer: (d)

direction-and-distance-verbal-reasoning

Clearly, they are 12 km apart.

Question : 3

Two buses start from the opposite points of a main road, 150 kms apart. The first bus runs for 25 kms and takes a right turn and then runs for 15 kms. It then turns left and runs for another 25 kms and takes the direction back to reach the main road. In the meantime, due to a minor breakdown, the other bus has run only 35 kms along the main road. What would be the distance between the two buses at this point ?

a) 80 kms

b) 75 kms

c) 65 kms

d) 85 kms

Answer: (c)

direction-and-distance-verbal-reasoning

Let X and Y be two buses.

Bus X travels along the path

PA, AB, BC, CD

Now, AD = BC = 25 km.

So, PD = PA + AD = 50km.

Bus Y travels 35 km upto E.

∴ Distance between two buses = PQ - (PD - QE)

= [150 - (50 + 35)] = 65km.

Question : 4

Rahul is facing west. Then he turned right three times and walked straight for a distance of 15 km, 15 km, and 35 km respectively, How far is he from starting point ?

a) 25 km

b) 20 km

c) 15 km

d) 30 km

Answer: (a)

direction-and-distance

Let his starting point is S.

AB = SC =15 m, BC = AS = 15km

BD - BC = 35 - 15 = 20 km

SD = $√{SC^2 + CD^2}$ = $√{15^2 + 20^2}$

= $√{225 + 400}$ = $√{625}$ = 25km

Question : 5

Shyam walked 6 metres facing towards East, then took a right turn and walked a distance of 9 metres. He then took a left turn and walked a distance of 6 metres. How far is he from the starting point ?

a) 21 metres

b) Can't be determined

c) 15 metres

d) 18 metres

e) None of these

Answer: (c)

direction-and-distance

Movements of Shyam are as shown in the figure given below:

A = Starting point D = End point

AD = $√{AE^2 + ED^2}$ ; Here AE = AB + BE (=CD)

= (6 + 6) = 12m & ED = BC = 9 m

∴ AD = $√{12^2 + 9^2}$ = $√{144 + 81}$ = $√{225}$ = 15m

Question : 6

Anushka starts from point L and walks 10m towards north. She then turns to her right and walks 5m. Again she turns to her left and walks 10m and then she takes one more left turn of 5m up to the point M. How far is she from her starting point L?

a) 20 metre

b) 30 metre

c) 5 metre

d) 25 metre

Answer: (a)

direction-and-distance-verbal-reasoning

Required distance

= LM = LA + AM

= (10 + 10) metre

= 20 metre

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