find distance only Detailed Explanation And More Example
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The following question based on direction & distance sense test topic of verbal reasoning
(a) 30 metres
(b) 60 metres
(c) 50 metres
(d) 10 metres
The correct answers to the above question in:
Answer: (c)
AE = (30 + 20) metres
= 50 metres
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Read more finding distance sense test Based Verbal Reasoning Questions and Answers
Question : 1
Rana travels 10km North, turns left and travels 4 km and then again turns right and covers another 5 km. He then turns to right – hand side and travels another 4 km. How far is he from the point of starting of his journey?
a) 4 km
b) 10 km
c) 5 km
d) 15 km
Answer »Answer: (d)
Required distance
= (10+5) km = 15 Km
Question : 2
Kailash walks 3 kms to East and turns South and walks 4 kms. Again turns West and walks 6 kms. How far is he from the starting point?
a) 7 kms
b) 5 kms
c) 6 kms
d) 3 kms
Answer »Answer: (b)
Required distance
AD = $√{AE^2 + DE^2}$
= $√{4^2 + 3^2}$
= $√{16 + 9}$
= $√{25}$
= 5 km
Question : 3
M starts from his office and goes 15 km southwards, he then proceeds 5 km to the right. He then travels 7 km to the left, again travels 7 km to the left and eventually goes 22 km towards left. Measure the distance between the final and starting point.
a) 2 km
b) 4 km
c) 3 km
d) 1 km
Answer »Answer: (a)
Question : 4
Ravi starts from his house and moves towards south. He walks 100 m, then turns left and walks 200 m, turns right and walks 500. How far is he from his house?
a) 800 m
b) 200$√{2}$ m
c) 400$√{5}$ m
d) 200$√{10}$ m
e) None of these
Answer »Answer: (d)
Ravi starts from O and finished at C.
OC = $√{OD^2 + CD^2}$ = $√{OD^2 + (DA + AC)^2}$
= $√{(200)^2 + (100 + 500)^2}$ m
= $√{200 × 200 + 600 × 600}$ m
= 100 $√{4 + 36}$ m = 100 $√{40}$ m = 200 $√{10}$ m
[OD = AB = 200 m ; DA = OB = 100 m and AC = 500 m]
Question : 5
A bus starts from point A and runs 20 kms towards South, turns to its right and runs 25 km. It then turns right again runs 20 km. Afterwards it runs 5 km in the East direction and reaches point B. How far is the bus from the starting point ?
a) 20 km
b) 30 km
c) 35 km
d) 25 km
Answer »Answer: (a)
Required distance
AB = 20 km
Question : 6
A child is looking for his mother. He went 80 meters in the East before turning to his right. He went 20 meters before turning to his right again to trace his mother at his married sister's house, 20 meters from this point. His mother was not there. From there he went 100 meters to his north where he met his mother who was shopping there in the market. How far did the son meet from the starting point?
a) 60 m
b) 140 m
c) 80 m
d) 100 m
Answer »Answer: (d)
AE = AB – EB
= 80 – 20 = 60m
EF = DF – DE
= 100 - 20 = 80m
Now in Δ AEF,
AF = $√{(AE)^2 + (EF)^2}$
= $√{60^2 + 80^2}$
= $√{3600 + 6400}$ = $√{10000}$ = 100m
GET direction & distance sense test PRACTICE TEST EXERCISES
find directions only
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find both direction & distance section 3
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