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The following question based on direction & distance sense test topic of verbal reasoning

Questions : Rasik walks 20 m North. Then he turns right and walks 30 m. Then he turns right and walks 35 m. Then he turns left and walks 15 m. Then he again turns left and walks 15 m. In which direction and how many metres away is he from his original position?

(a) 15 metres West

(b) 30 metres East

(c) 30 metres West

(d) 45 metres East

e) None of these

The correct answers to the above question in:

Answer: (d)

The movements of Rasik from A to F are as shown in Fig. 35.

Since, CD = AB + EF, so F lies in line with A.

Therefore, Rasik's distance from original position A = AF = (AG + GF)

= (BC = DE)

= (30 + 15) m = 45 m.

Also, F lies to the east to A.

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Read more finding both direction distance test Based Verbal Reasoning Questions and Answers

Question : 1

Saiyeev walks 10 metres towards the South. Turning to the left, he walks 20 metres and then moves to his right. After moving a distance of 20 metres, he turns to the right and walks 20 metres. Finally, he turns to the right and moves a distance of 10 metres. How far and in which direction is he from the starting point ?

a) 20 metres South

b) 10 metres North

c) 10 metres South

d) 20 metres.North

e) None of these

Answer: (a)

direction-and-distance-verbal-reasoning

The movement of Sanjeev from A to F are as shown in Figure

Clearly, Sanjeev's distance from starting point A

= AF = (AB + BF)

= AB + (BE - EF) = AB + (CD - EF)

= [10 + (20 - 10)] = (10 + 10) m

= 20 m.

Also, F lies to the South of A.

So, Sanjeev is 20 metres to the south of his starting point.

Question : 2

Kunal walks 10 kilometres towards North. From there, he walks 6 kilometres towards South. Then, he walks 3 kilometres towards East. How far and in which direction is he with reference to his starting point?

a) 7 kilometres East

b) 5 kilometres West

c) 7 kilometres West

d) 5 kilometres North-east

Answer: (d)

direction-and-distance

The movements is as shown in figure.

AC = (AB – BC) = (10 – 6) km = 4 km.

Clearly, D is to the Northeast of A.

So, Kunal’s distance from starting point A

= AD = $√{AC^2 + CD^2}$

= $√{4^2 + 3^2}$ = $√{25}$

= 5 km.

So, it is 5 km to the North-east of his starting point

Question : 3

A school bus driver starts from the school, drives 2 km. towards North, takes a left turn and drives for 5 km. he then takes a left turn and drives for 8 km. before taking a left turn again and driving for further 5 km. The driver finally takes a left turn and drives 1 km. before stopping. How far and towards which direction should the driver drive to reach the school again?

a) 6 km. towards west

b) 3 km. towards Nort

c) 6 km. towards south

d) 7 km. towards east

e) 5 km. towards north

Answer: (e)

direction-and-distance

Question : 4

Starting from a point P, Sachin walked 20 metres towards South. He turned left and walked 30 metres. He then turned left and walked 20 metres. He again turned left and walked 40 metres and reached a point Q. How far and in which direction is the point Q from the point P?

a) 20 metres West

b) 10 metres North

c) 10 metres West

d) 10 metres East

e) None of these

Answer: (c)

The movements of Sachin are as shown Fig. 27

(P to B, B to C, C to D and D to Q).

Clearly, distance of Q from P = PQ = (DQ - PD)

= (DQ - BC)

= (40 - 30) m = 10 m

Also, Q is to the west of P.

Therefore, Q is 10 m west of P.

Question : 5

Rohit walked 25 metres towards South. Then he turned to his left and walked 20 metres. He then turned to his left and walked 25 metres. He again turned to his right and walked 15 metres. At what distance is he from the starting point and in which direction?

a) 35 metres East

b) 40 metres East

c) 35 metres North

d) 60 metres East

e) None of these

Answer: (a)

The movements of Rohit are as shown in Fig. 26.

Therefore, Rohit's distance from starting point A = AE = (AD + DE)

= (BC + DE) = (20 + 15) m = 35 m.

Also, E is to the East of A.

Question : 6

Sanjeev walks 10 metres towards the South. Turning to the left, he walks 20 metres and then moves to his right. After moving a distance of 20 metres, he turns to the right and walks 20 metres. Finally, he turns to the right and moves a distance of 10 metres. How far and in which direction is he from the starting point?

a) 10 metres North

b) 20 metres South

c) 20 metres North

d) 10 metres South

e) None of these

Answer: (b)

The movements of Sanjeev from A to F are as shown in Fig. 22.

Clearly, Sanjeev's distance from starting point A = AF = (AB + BF)

= AB + (BE - EF)

= AB + (CD - EF)

= [10 + (20 - 10)] m

= (10 + 10) m = 20 m.

Also, F lies to the south of A. So, Sanjeev is 20 metres to the south of his starting point.

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