find both direction & distance Detailed Explanation And More Example

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The following question based on direction & distance sense test topic of verbal reasoning

Questions : Sharada started to move in the direction of South. After moving 15 m, she turned to her left twice and moved 15 m each time. Now, how far is she and in which direction from her starting point?

(a) 20 m, west

(b) 15 m, East

(c) 15 m, South

(d) 30 m, East

The correct answers to the above question in:

Answer: (b)

Let Sharada starts from point A and passing through B and C, she reaches D.

Clearly, she is in East and at a distance of 15 m from her original position.

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Read more finding both direction distance test Based Verbal Reasoning Questions and Answers

Question : 1

Rachel starts walking towards North. After walking 15 m, she turns towards South and walks 20 m. She then turns towards East and walks 10 m. Then, again she walks 5 m towards North. How far is she from her starting point and in which direction?

a) 10 m, West

b) 5 m, East

c) 5 m, North

d) 10 m, East

Answer: (d)

Let the initial point of Rachel be 'A'.

Therefore, Required distance, AE = 10 m

So, Rachel is 10 m towards East from the starting point.

Directions for the following questions:
Read the following information carefully and answer the questions that follow.

  • Point H is 6 m towards the East of points G.
  • Point R is 8 m North of point G.
  • Point Q is exactly midway between point R and point G.
  • Point K is 10 m to the South of point Q.
  • Point L is 3 m towards the East of point Q.
  • Point S is exactly midway between point G and point H.
[I.B.P.S. (PO) 2012]

Question : 2

If a persons walks 4 m towards the South from point L, takes a right turn and walks for another 3 m, then which of the following points would be reach?

a) Q

b) G

c) K

d) H

e) None of these

Answer: (b)

Clearly, the person starts from L goes 4 m southward and reaches point S from where he takes right turn and walks 3 m to reach G.

Question : 3

If a persons walks 8 m towards North from point S, then which of the following points would he cross and how far will he be from point R?

a) G, 4 m

b) H, 3 m

c) L, 6 m

d) L, 3 m

e) G, 8 m

Answer: (d)

Clearly, man will cross L and at the final point, he will be at a distance of 3 m from R.

Question : 4

In an exercise, Krishnan walked 25 m towards South and then he turned to his left and moved for 20 m. He again turned to his left and walked 25 m. Thereafter, he turned to his right and walked 15 m. What is the distance and direction of his present location with reference to the starting point?

a) 74 m, North - East

b) 60 m, North

c) 35 m, East

d) 40 m, South - East

Answer: (c)

According to the question, the direction diagram will be as follows.

Now, AB = CD = 25 km, BC = AD = 20 m, DE = 15 m

Therefore, Required distance, AE = AD + DE AE = (20 + 15) = 35 m

Also, E is to the East of A.

Question : 5

Rajnikanth left his home foe office in car. He drove 15 km straight towards North and then turned Eastwards and covered 8 km. He, then turned to left and covered 1 km. He again turned left and drove for 20 km and reached office. How far and in what direction in his office from the home?

a) 21 km, West

b) 15 km, North - East

c) 20 km, North - West

d) 26 km, North - West

Answer: (c)

According to the question, the direction diagram will be as follows.

Now, AB = 15 km, CD = BF = 1 km

AF = AB + BF = 15 + 1 = 16 km

DE = 20 km DF = BC = 8 km

EF = DE - DF = 20 - 8 = 12 km

Therefore, Required distance, AE = $√{(AF)^2 + (EF)^2}$

= $√{(16)^2 + (12)^2}$

= $√{(256 + 144)}$ = √400 = 20 km

So, his office is 20 km North - West.

 

Question : 6

A school bus driver starts from the school, drives 2 km towards North, takes a left turn and drives for 5 km. He, then takes a left turn and drives for 8 km before taking a left turn again and driving for further 5 km. The driver finally takes a left turn and drives 1 km before stopping. How far and towards which direction should the driver drive to reach the school again?

a) 3 km towards North

b) 7 km towards East

c) 6 km towards South

d) 6 km towards West

e) 5 km towards North

Answer: (e)

According to the question, the direction diagram will be as follows.

Now, BC = DE = 5 km, CD = BE = 8 km AB = 2 km, EF = 1 km

Therefore, Required distance, AF = BE - (AB + EF) = 8 - (2 + 1) = 8 - 3 = 5 km.

From the direction diagram, it is clear that the bus is present finally in the South direction of school.

So, the driver needs to drive 5 km towards North direction to reach the school.

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