find both direction & distance Detailed Explanation And More Example

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The following question based on direction & distance sense test topic of verbal reasoning

Questions : Amit starts from point A and walks 5 m towards North-East direction and reaches point B. From here, he travels 8 m in the East direction and reaches point C. From C, he travels towards South-West direction and reaches point D after travelling a distance equal to AB. At last, he turns towards the West direction and reaches point A. How much distance has been covered by Amit and which geometrical figure has been formed by the path travelled by him?

(a) 16 m, parellelogram

(b) 26 m, parellelogram

(c) 26 m, square

(d) 26 m, trapezium

The correct answers to the above question in:

Answer: (b)

According to the question, the direction diagram is as follows. 

Therefore, Required distance = AB + BC + CD + DA

= 5 + 8 + 5 + 8 = 26 m.

and the geometrical figure formed is Parallelogram.

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Read more finding both direction distance test Based Verbal Reasoning Questions and Answers

Question : 1

Sanjay's school is 10 $√2$ km in North - West direction from his house. The officee of his father is 10 km in South direction from the school. The multiplex hall is 10 km towards East from the school. How far and in which direction is the multiplex hall from the office of his father?

a) $10√2$ km, north - East

b) 20 km, North - East

c) 10 km, South - East

d) $20√2$ km, north - East

e) Cannot be determined

Answer: (a)

According to the question, the direction diagram will be as follows.

As in a square, diagonals are equal. Therefore, SH = OM = 10√2 km

Therefore, Required distance, OM = Distance between office and multiplex = 10√2 km

Also, it is clear from diagram that multiplex (M) is to the North - East of O (office)

So, the multiplex is $10√2$ km North - East from office.

Question : 2

Pankaj travels 10 m in North direction, he turns right and travels 20 m. Again he turns towards right and travels 25 m. Then, he turns towards left and travels 15 m. In which direction and how far is Pankaj from his original position?

a) 35 m, East

b) 10 m, West

c) 25 m, East

d) 55 m, West

e) None of these

Answer: (e)

According to the question, the direction diagram will be as follows.

A = Starting point, E = Finishing point DE = 15 m,

BC = FD = 20 m FE = FD + DE = 20 + 15 = 35 m

AF = BF - AB = 25 - 10 = 15 m

Therefore, Required distance, AE = $√{(AF)^2 + (FE)^2}$

= $√((15)^2 + (35)^2)$

= $√{(225 + 1225)}$

= $√1450$

and the direction is South-East

Question : 3

Starting from a point, raju walked 12 ft North, he turned right and walked 10 ft, he again turned right and walked 12 ft, then the turned left and walked 5 ft. How far is he now and in which direction from the starting point?

a) 27 ft towards East

b) 5 ft towards East

c) 10 ft towards West

d) 15 ft towards East

e) 35 ft towards North

Answer: (d)

According to the questions, the direction diagram is as follows.

AB = CD = 12 ft

BC = AD = 10 ft

DE = 5 ft

Therefore, Required distance, AE = AD + DE = 10 + 5 = 15 ft

Hence at finishing point E, Raju is 15 ft East from starting point A.

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