find both direction & distance Detailed Explanation And More Example

MOST IMPORTANT verbal reasoning - 15 EXERCISES

Top 10,000+ Verbal Memory Based Exercises

DIRECTIONS:

Study the following information to answer the questions given below :

Ramu walks 2 km towards North and turn to his right and walks 4 km more. He then turns to his right and walks 4 km and turns again to his right and walks another 4 km.

[SSC CPO Sub-Inspector 2007]

The following question based on direction & distance sense test topic of verbal reasoning

Questions : Which direction is Ramu facing now ?

(a) South

(b) North

(c) West

(d) East

The correct answers to the above question in:

Answer: (c)

direction-and-distance-verbal-reasoning

Ramu is facing towards west.

Practice direction & distance sense test (find both direction & distance) Online Quiz

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Read more finding both direction distance test Based Verbal Reasoning Questions and Answers

Question : 1

How far away is Ramu from the starting point ?

a) 6 km

b) 4 km

c) 8 km

d) 2 km

Answer: (d)

direction-and-distance-verbal-reasoning

Ramu is 2 km away from the starting point.

DIRECTIONS:

Study the information given below carefully and answer the questions that follow :

On a playing ground, Dinesh, Kunal, Nitin, Atul and Prashant are standing as described below facing the North.

  1. Kunal is 40 metres to the right of Atul.
  2. Dinesh is 60 metres to the south of Kunal.
  3. Nitin is 25 metres to the west of Atul.
  4. Prashant is 90 metres to the north of Dinesh.

Question : 2

Who is to the north-east of the person who is to the left of Kunal ?

a) Nitin

b) Dinesh

c) Either Nitin or Dinesh

d) Atul

e) None of these

Answer: (e)

Clearly, the Arrangement of Boys is as shown below:

direction-and-distance-verbal-reasoning

Clearly, Atul is to the left of Kunal and Prashant is to the North-East of Atul.

Question : 3

If a boy walks from-Nitin, meets Atul followed by Kunal, Dinesh and then Prashant, how many metres has he walked if he has travelled the straight distance all through ?

a) 185 metres

b) 155 metres

c) 245 metres

d) 215 metres

e) None of these

Answer: (d)

Clearly, the Arrangement of Boys is as shown below:

direction-and-distance-verbal-reasoning

Required distance = NA + AK + KD + DP

= (25 + 40 + 60 + 90) = 215m.

Question : 4

Rohit walked 25 metres towards South. Then he turned to his left and walked 20 metres. He then turned to his left and walked 25 metres. He again turned to his right and walked 15 metres. At what distance is he from the starting point and in which direction?

a) 40 metres East

b) 35 metres East

c) 60 metres East

d) 35 metres North

Answer: (b)

direction-and-distance

The movements of Rohit are as shown in fig.

∴ Rohit's distance from starting point A =

AE = AD + DE = BC + DE = (20 + 15)m = 35 m

Also, E is to the East of A

Question : 5

Maya starts at point T, Walks straight to point U which is 4 ft away. She turns left at 90° and walks to W which is 4 ft away, turns 90° right and goes 3 ft to P, turns 90° right and walks 1 ft to Q, turns left at 90° and goes to V, which is 1 ft away and once again turns 90° right and goes to R, 3 ft away. What is the distance between T and R ?

a) 8 ft

b) 4 ft

c) 7 ft

d) 5 ft

e) None of these

Answer: (a)

The movements of Maya from T to R are as shown in Figure.

Distance between T and R

= TR = TU + UR

= TU + PW + QV

= (4 + 3 + 1)ft = 8 ft.

direction-and-distance

Question : 6

Kunal walks 10 kilometres towards North. From there, he walks 6 kilometres towards south. Then, he walks 3 kilometres towards east. How far and in which direction is he with reference to his starting point?

a) 7 kilometres West

b) 5 kilometres West

c) 7 kilometres East

d) 5 kilometres North-east

e) None of these

Answer: (e)

Using of Pythagoras,

H2 = P2 + B2

H2 = (4)2 + (3)2 = 16 + 9 = 25

H2 = 25, H = 5 km (– 5 km can not possible)

direction-and-distance

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