find both direction & distance Detailed Explanation And More Example
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DIRECTIONS:
Read the following information for answering the questions that follows :
In a playground, A, B, C, D, & E are standing as described below facing the North.
- B is 50m to the right of D.
- A is 60m to the South of B.
- C is 40m to the west of D.
- E is 80m to the north of A.
The following question based on direction & distance sense test topic of verbal reasoning
(a) 170
(b) 120
(c) 230
(d) 150
The correct answers to the above question in:
Answer: (c)
Total distance walked by the boy.
= 40 + 50 + 60 + 80 = 230 m
Discuss Form
Read more finding both direction distance test Based Verbal Reasoning Questions and Answers
Question : 1
Kunal walks 10 kilometres towards North. From there, he walks 6 kilometres towards south. Then, he walks 3 kilometres towards east. How far and in which direction is he with reference to his starting point?
a) 7 kilometres West
b) 5 kilometres West
c) 7 kilometres East
d) 5 kilometres North-east
e) None of these
Answer »Answer: (e)
Using of Pythagoras,
H2 = P2 + B2
H2 = (4)2 + (3)2 = 16 + 9 = 25
H2 = 25, H = 5 km (– 5 km can not possible)
Question : 2
Maya starts at point T, Walks straight to point U which is 4 ft away. She turns left at 90° and walks to W which is 4 ft away, turns 90° right and goes 3 ft to P, turns 90° right and walks 1 ft to Q, turns left at 90° and goes to V, which is 1 ft away and once again turns 90° right and goes to R, 3 ft away. What is the distance between T and R ?
a) 8 ft
b) 4 ft
c) 7 ft
d) 5 ft
e) None of these
Answer »Answer: (a)
The movements of Maya from T to R are as shown in Figure.
Distance between T and R
= TR = TU + UR
= TU + PW + QV
= (4 + 3 + 1)ft = 8 ft.
Question : 3
Rohit walked 25 metres towards South. Then he turned to his left and walked 20 metres. He then turned to his left and walked 25 metres. He again turned to his right and walked 15 metres. At what distance is he from the starting point and in which direction?
a) 40 metres East
b) 35 metres East
c) 60 metres East
d) 35 metres North
Answer »Answer: (b)
The movements of Rohit are as shown in fig.
∴ Rohit's distance from starting point A =
AE = AD + DE = BC + DE = (20 + 15)m = 35 m
Also, E is to the East of A
Question : 4
Who is to the South-East of the person who is to the left of D?
a) C
b) A
c) E
d) B
Answer »Answer: (b)
Question : 5
What is the minimum distance (in metre approximately) between C and E?
a) 92
b) 53
c) 120
d) 78
Answer »Answer: (a)
CE = $√{BC^2 + BE^2}$ = $√{90^2 + 20^2}$
= $√{8100 + 400}$ = $√{8500}$ = 92.19m
Question : 6
Starting from a point P, Sachin walked 20 metres towards South. He turned left and walked 30 metres. He then turned left and walked 20 metres. He again turned left and walked 40 metres and reached a point Q. How far and in which direction is the point Q from the point P ?
a) 10 metres East
b) 20 metres West
c) 10 metres North
d) 10 metres West
e) None of these
Answer »Answer: (d)
The movement of Sachin is as shown in Figure
(P to B, B to C, C to D and D to Q)
Clearly, the distance of Q from P
= PQ = (DQ - PQ) = (DQ - BC)
= (40 - 30)m = 10m.
Also, Q is to the west of P
∴ Q is 10m West of P.
GET direction & distance sense test PRACTICE TEST EXERCISES
find directions only
find distance only
find both direction & distance
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find distance only section 2
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find distance only section 5
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find both direction & distance section 2
find both direction & distance section 3
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