find both direction & distance Detailed Explanation And More Example

MOST IMPORTANT verbal reasoning - 15 EXERCISES

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DIRECTIONS:

Read the following information for answering the questions that follows :

In a playground, A, B, C, D, & E are standing as described below facing the North.

  1. B is 50m to the right of D.
  2. A is 60m to the South of B.
  3. C is 40m to the west of D.
  4. E is 80m to the north of A.

The following question based on direction & distance sense test topic of verbal reasoning

Questions : What is the minimum distance (in metre approximately) between C and E?

(a) 92

(b) 53

(c) 120

(d) 78

The correct answers to the above question in:

Answer: (a)

CE = $√{BC^2 + BE^2}$ = $√{90^2 + 20^2}$

= $√{8100 + 400}$ = $√{8500}$ = 92.19m

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Read more finding both direction distance test Based Verbal Reasoning Questions and Answers

Question : 1

Who is to the South-East of the person who is to the left of D?

a) C

b) A

c) E

d) B

Answer: (b)

Question : 2

If a boy walks from C, meet D followed by B, A and then E, how many meters has he walked if he has travelled the straight distance all through?

a) 170

b) 120

c) 230

d) 150

Answer: (c)

Total distance walked by the boy.

= 40 + 50 + 60 + 80 = 230 m

direction-and-distance

Question : 3

Kunal walks 10 kilometres towards North. From there, he walks 6 kilometres towards south. Then, he walks 3 kilometres towards east. How far and in which direction is he with reference to his starting point?

a) 7 kilometres West

b) 5 kilometres West

c) 7 kilometres East

d) 5 kilometres North-east

e) None of these

Answer: (e)

Using of Pythagoras,

H2 = P2 + B2

H2 = (4)2 + (3)2 = 16 + 9 = 25

H2 = 25, H = 5 km (– 5 km can not possible)

direction-and-distance

Question : 4

Starting from a point P, Sachin walked 20 metres towards South. He turned left and walked 30 metres. He then turned left and walked 20 metres. He again turned left and walked 40 metres and reached a point Q. How far and in which direction is the point Q from the point P ?

a) 10 metres East

b) 20 metres West

c) 10 metres North

d) 10 metres West

e) None of these

Answer: (d)

direction-and-distance-verbal-reasoning

The movement of Sachin is as shown in Figure

(P to B, B to C, C to D and D to Q)

Clearly, the distance of Q from P

= PQ = (DQ - PQ) = (DQ - BC)

= (40 - 30)m = 10m.

Also, Q is to the west of P

∴ Q is 10m West of P.

Question : 5

A man leaves for his office from his house. He walks towards East. After moving a distance of 20 m, he turns towards South and walks 10 m. Then he walks 35 m towards the West and further 5 m towards the North. He then turns towards East and walks 15 m. What is the straight distance in metres between his initial and final positions ?

a) 5

b) 0

c) Cannot be determined

d) 10

e) None of these

Answer: (a)

direction-and-distance-verbal-reasoning

 The movement of the man from A to F are as shown in Figure

Clearly, DC = AB + EF.

∴ F is in line with A.

Also, AF = (BC - DE) = 5 m.

So, the man is 5 metres away from his initial position.

Question : 6

Rohit walked 25 metres towards South. Then he turned to his left and walked 20 metres. He then turned to his left and walked 25 metres. He again turned to his right and walked 15 metres. At what distance is he from the starting point rind in which direction ?

a) 35 metres North

b) 35 metres East

c) 60 metres East

d) 40 metres East

e) None of these

Answer: (b)

direction-and-distance-verbal-reasoning

The movement of Rohit is as shown in Figure

∴ Rohit's distance from starting point A

= AE = (AD + DE)

= (BC + DE) = (20 + 15) = 35m

Also, E is the East of A.

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