find both direction & distance Detailed Explanation And More Example
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The following question based on direction & distance sense test topic of verbal reasoning
(a) 35 metres North
(b) 35 metres East
(c) 60 metres East
(d) 40 metres East
e) None of these
The correct answers to the above question in:
Answer: (b)
The movement of Rohit is as shown in Figure
∴ Rohit's distance from starting point A
= AE = (AD + DE)
= (BC + DE) = (20 + 15) = 35m
Also, E is the East of A.
Discuss Form
Read more finding both direction distance test Based Verbal Reasoning Questions and Answers
Question : 1
A man leaves for his office from his house. He walks towards East. After moving a distance of 20 m, he turns towards South and walks 10 m. Then he walks 35 m towards the West and further 5 m towards the North. He then turns towards East and walks 15 m. What is the straight distance in metres between his initial and final positions ?
a) 5
b) 0
c) Cannot be determined
d) 10
e) None of these
Answer »Answer: (a)
The movement of the man from A to F are as shown in Figure
Clearly, DC = AB + EF.
∴ F is in line with A.
Also, AF = (BC - DE) = 5 m.
So, the man is 5 metres away from his initial position.
Question : 2
Starting from a point P, Sachin walked 20 metres towards South. He turned left and walked 30 metres. He then turned left and walked 20 metres. He again turned left and walked 40 metres and reached a point Q. How far and in which direction is the point Q from the point P ?
a) 10 metres East
b) 20 metres West
c) 10 metres North
d) 10 metres West
e) None of these
Answer »Answer: (d)
The movement of Sachin is as shown in Figure
(P to B, B to C, C to D and D to Q)
Clearly, the distance of Q from P
= PQ = (DQ - PQ) = (DQ - BC)
= (40 - 30)m = 10m.
Also, Q is to the west of P
∴ Q is 10m West of P.
DIRECTIONS:
Read the following information for answering the questions that follows :
In a playground, A, B, C, D, & E are standing as described below facing the North.
- B is 50m to the right of D.
- A is 60m to the South of B.
- C is 40m to the west of D.
- E is 80m to the north of A.
Question : 3
What is the minimum distance (in metre approximately) between C and E?
a) 92
b) 53
c) 120
d) 78
Answer »Answer: (a)
CE = $√{BC^2 + BE^2}$ = $√{90^2 + 20^2}$
= $√{8100 + 400}$ = $√{8500}$ = 92.19m
Question : 4
Rasik walks 20 m North. Then he turns right and walks 30 m. Then he turns right and walks 35 m. Then he turns left and walks 15 m. Then he again turns left and walks 15 m. In which direction and how many metres away is he from his original position ?
a) 30 metres East
b) 15 metres West
c) 45 metres East
d) 30 metres West
Answer »Answer: (c)
The movement of Rasik from A to F is as shown in Figure
Since CD = AB + EF, so F lies in the line with A.
∴ Rasik's distance from original position A
= AF = (AG + GF)
= (BC + DE) = (30 + 15)m = 45m
Also, F lies to the East of A
Question : 5
Kishenkant walks \0 kilometres towards North. From there, he walks 6 kilometres towards South. Then, he walks 3 kilometres towards East. How far and in which direction is he with reference to his starting point ?
a) 5 kilometres North-east
b) 5 kilometres West
c) 7 kilometres West
d) 7 kilometres East
Answer »Answer: (a)
The movement of Kishenkant is as shown in the figure.
(A to B, B to C and C to D).
AC = (AB - BC)
= (10 - 6)km = 4km
Clearly, D is to the North-east of A.
∴ Kishenkant's distance from starting point A
= AD = $√{AC^2 + CD^2}$
= $√{4^2 + 3^2}$ = $√{25}$
= 5km.
So, Kishenkant is 5km to the North-east of his starting point.
DIRECTIONS:
The following questions are based on the diagram given below showing four persons stationed at the four corners of a square piece of plot as shown.
Question : 6
From the original position given in the above figure, A and B move one arm length clockwise and then cross over to the corner diagonally opposite; C and D move one arm length anti-clockwise and cross over the comer diagonally opposite. The original configuration ADBC has now changed to
a) BDAC
b) CBDA
c) ACBD
d) DACB
e) BCAD
Answer »Answer: (b)
Clearly, (i), (ii), (iii) and (iv) show the movements of A, B, C and D respectively while the new arrangement so obtained is shown in (v).
So, the configuration changes to CBDA.
GET direction & distance sense test PRACTICE TEST EXERCISES
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