find both direction & distance Detailed Explanation And More Example
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DIRECTIONS:
The following questions are based on the diagram given below showing four persons stationed at the four corners of a square piece of plot as shown.
The following question based on direction & distance sense test topic of verbal reasoning
(a) At the north-east corner
(b) At the north-west corner
(c) At the south-west corner
(d) At the south-east corner
e) Midway between original position of B and D
The correct answers to the above question in:
Answer: (c)
The movements of A, B, C and D are shown in figure (i), (ii), (iii) and (iv) respectively.
The final configuration is shown in (v).
Comapring (v) with the diagram, A is in the South-West corner.
Discuss Form
Read more finding both direction distance test Based Verbal Reasoning Questions and Answers
Question : 1
A square field ABCD of side 90 m is so located that its diagonal AC is from north to south and the corner B is to the west of D. Rohan and Rahul start walking along the sides from B and C respectively in the clockwise and anticlockwise directions with speeds of 8 km/hr and 10 km/hr. Where shall they cross each other the second time ?
a) On BC at a distance of 10 m from B
b) On AD at a distance of 30 m from A
c) On BC at a distance of 10 m from C
d) On AD at a distance of 30 m from D
Answer »Answer: (c)
Clearly, the arrangement is as shown in the adjioning figure.
Rohan's speed = 8 km/hr.
= $8000/{60 x 60}$ m/sec = $20/9$ m/sec.
Rahul's speed = 10 km/hr.
= $10000/{60 x 60}$ m/sec = $25/9$ m/sec.
Since Rohan and Rahul are moving in opposite directions, so they together cover a distance of $({20}/9 + {25}/9)$
i.e., $45/9$ or 5 meters in one second.
To meet at a point, they together have to cover the distance (CD + DA + AB) i.e., 270m.
Now, 5 meters is covered in 1 second.
So, 270 m will be covered in $(1/{5} x 270)$ = 54 seconds.
Now, distance covered by Rohan in 54 seconds = $({20}/9 x 54)$ m = 120 m.
distance covered by Rahul in 54 seconds = $({25}/9 x 54)$ m = 150 m.
Thus, Rohan and Rahul meet for the first time on AD at a point 30 m from A and 60 m from D.
Now, to meet again, Rohan and Rahul will have to complete one full round i.e. together move a distance of 360 m.
5 metres is covered by both together in 1 second.
Thus, 360 m will be covered by both in $({1}/5 x 360)$ = 72 seconds.
Now, distance covered by Rohan in 72 seconds = $({20}/9 x 72)$ = 160 m.
Distance covered by Rahul in 72 seconds = $({25}/9 x 72)$ = 200 m.
Thus, Rohan and Rahul meet on BC at a point 10 m from C and 80 m from B.
Question : 2
From the original position given in the above figure, A and B move one arm length clockwise and then cross over to the corner diagonally opposite; C and D move one arm length anti-clockwise and cross over the comer diagonally opposite. The original configuration ADBC has now changed to
a) BDAC
b) CBDA
c) ACBD
d) DACB
e) BCAD
Answer »Answer: (b)
Clearly, (i), (ii), (iii) and (iv) show the movements of A, B, C and D respectively while the new arrangement so obtained is shown in (v).
So, the configuration changes to CBDA.
Question : 3
Kishenkant walks \0 kilometres towards North. From there, he walks 6 kilometres towards South. Then, he walks 3 kilometres towards East. How far and in which direction is he with reference to his starting point ?
a) 5 kilometres North-east
b) 5 kilometres West
c) 7 kilometres West
d) 7 kilometres East
Answer »Answer: (a)
The movement of Kishenkant is as shown in the figure.
(A to B, B to C and C to D).
AC = (AB - BC)
= (10 - 6)km = 4km
Clearly, D is to the North-east of A.
∴ Kishenkant's distance from starting point A
= AD = $√{AC^2 + CD^2}$
= $√{4^2 + 3^2}$ = $√{25}$
= 5km.
So, Kishenkant is 5km to the North-east of his starting point.
Question : 4
A starts crossing the field diagonally. After walking half the distance, he turns right, walks some distance and turns left. Which direction is A facing now ?
a) North-west
b) North-east
c) South-east
d) North
e) South-west
Answer »Answer: (a)
Clearly, the route of A is as shown.
Comparing it with the given diagrams, the direction of A will be North-West.
Question : 5
After the movements given in Q. 41 above, who is at the north-west corner ?
a) B
b) A
c) D
d) C
e) None of these
Answer »Answer: (d)
Clearly, C is at the north-west corner
Question : 6
From the original position, B and D move one and a half length of sides clockwise and anticlockwise respectively. Which one of the following statements is true ?
a) D is at the midpoint between A and C, and B at the corner originally occupied by C.
b) B and D are both at the midpoint between A and C.
c) B is at the midpoint between A and Ct and D at the midpoint between the original position of B and C
d) B and D are both at the midpoint between A and D.
Answer »Answer: (b)
The movements of B and D are clearly shown in the adjoining diagram.
So, statements (a) is true.
GET direction & distance sense test PRACTICE TEST EXERCISES
find directions only
find distance only
find both direction & distance
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find distance only section 2
find distance only section 3
find distance only section 4
find distance only section 5
find distance only section 6
find both direction & distance section 2
find both direction & distance section 3
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