find both direction & distance Detailed Explanation And More Example

Answer: (b)

Q gets a North-facing flat and is not next to S means

S and U get digonally opposite flats means

R, next to U, gets a South facing flat and T gets a north facing flat means

So, from the above final arragement answer to this question will be;

The diagonally opposite pairs are SU and QP

Answer: (b)

Q gets a North-facing flat and is not next to S means

S and U get digonally opposite flats means

R, next to U, gets a South facing flat and T gets a north facing flat means

So, from the above final arragement answer to this question will be;

Clearly, all the statements are necessary to answer the given questions.

Answer: (d)

Q gets a North-facing flat and is not next to S means

S and U get digonally opposite flats means

R, next to U, gets a South facing flat and T gets a north facing flat means

So, from the above final arragement answer to this question will be;

The flat next to ITi flat is that of R, which remains unchanged if the flats of T and P are interchanged.

Answer: (d)

The movements is as shown in figure.

AC = (AB – BC) = (10 – 6) km = 4 km.

Clearly, D is to the Northeast of A.

So, Kunal’s distance from starting point A

= AD = $√{AC^2 + CD^2}$

= $√{4^2 + 3^2}$ = $√{25}$

= 5 km.

So, it is 5 km to the North-east of his starting point

Answer: (a)

The movement of Sanjeev from A to F are as shown in Figure

Clearly, Sanjeev's distance from starting point A

= AF = (AB + BF)

= AB + (BE - EF) = AB + (CD - EF)

= [10 + (20 - 10)] = (10 + 10) m

= 20 m.

Also, F lies to the South of A.

So, Sanjeev is 20 metres to the south of his starting point.

Answer: (d)

The movements of Rasik from A to F are as shown in Fig. 35.

Since, CD = AB + EF, so F lies in line with A.

Therefore, Rasik's distance from original position A = AF = (AG + GF)

= (BC = DE)

= (30 + 15) m = 45 m.

Also, F lies to the east to A.