SBI clerk prelims 22 Feb 2020 Questions and Answers Detailed Explanation

MOST IMPORTANT previous year question answers - 2 EXERCISES

Top 20,000+ All Competitive Exam Previous Year Question And Memory Based Exercises

Directions:

In each question two equations numbered (I) and (II) are given. You have to solve both the equations and mark appropriate answer.

[S.B.I. (CLERK) 2020]

The following question based on SBI clerk topic of previous year question answers

Questions : I. x2 + 4x - 45 = 0 and II. y2 - 13y + 40 = 0

(a) If x = y or no relation can be established

(b) If x > y

(c) If x < y

(d) If x ≥ y

e) If x ≤ y

The correct answers to the above question in:

Answer: (e)

I. x2 + 9x – 5x – 45 = 0

x(x + 9) – 5(x + 9) = 0

(x – 5) (x + 9) = 0

x = 5, - 9

II. y2 – 5y – 8y + 40 = 0

y(y – 5) – 8(y – 5) = 0

(y – 5) (y – 8) = 0 

Y= 5, 8

So, x ≤ y

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Read more sbi clerk 2020 prelims Based Previous Year Questions and Answers

Question : 1

A container contains mixture of milk & water in ratio 5 : 3 respectively. If 8 lit milk is added in it then ratio of milk to water becomes 11 : 5. Find difference between initial quantity of milk & that of water.

a) 5 lit

b) 38 lit

c) 18 lit

d) 30 lit

e) 10 lit

Answer: (e)

Let initial quantity of milk & water be 5x & 3x lit respectively

ATQ, $\text"5x+8"/\text"3x" = 11/5$

25x + 40 = 33x

⇒ x = 5

Required difference = 5x – 3x = 2x

= 10 lit

Question : 2

Rs 6000 when invested at a certain rate at SI for 2 years, it fetches Rs 1200. If the same sum is invested at the same rate for a year compounded half-yearly then find compound interest.

a) Rs 615

b) Rs 600

c) Rs 1200

d) Rs 585

e) Rs 1260

Answer: (a)

Let rate of interest be R%

ATQ, 1200 = $\text"6000×R×2"/100$

R = 10%

Since compounding is done half-yearly, rate of interest = 5%

Effective rate of interest = 5 + 5 + $\text"5×5"/100$ = 10.25%

Required interest = $\text"6000×10.25×1"/100$ = Rs 615

Question : 3

A boat can cover 28 km downstream in 42 min. ratio of speed of boat in still water to speed of stream is 7 : 3. Find difference between time taken by boat to cover 60 km downstream & 40 km upstream.

a) 2.25 hr

b) 1 hr

c) 1.5 h

d) 0.4 hr

e) 0.9 hr

Answer: (b)

Let speed of the boat in still water & speed of the stream be 7x & 3x kmph respectively

ATQ, $28/\text"7x+3x" = 42/60$

x = 4

Required difference = $40/\text"7x−3x" − 60/\text"7x+3x"$

= $4/x$  = 1 hour

Question : 4

I. 17x2 – 14x – 83 = - 80 and II. y2 = 2y + 35

a) If x = y or no relation can be established

b) If x > y

c) If x < y

d) If x ≥ y

e) If x ≤ y

Answer: (a)

I. 17x2 – 14x – 3 = 0

17x2 – 17x + 3x – 3 = 0

17x (x – 1) + 3(x – 1) = 0

(17x + 3) (x – 1) = 0

x = − 3 17 , 1

II. y2 – 2y – 35 = 0

y2 – 7y + 5y – 35 = 0

y(y −7) + 5(???? − 7) = 0

y = 7, - 5

So, no relation can be established

Question : 5

I. x2 = 81 and II. y2 = 64

a) If x = y or no relation can be established

b) If x > y

c) If x < y

d) If x ≥ y

e) If x ≤ y

Answer: (a)

I. x = ± 9

II. y = ± 8

So, no relation can be established

Question : 6

I. x2 + 2x – 35 = 0 and II. y2 + 15y + 56 = 0

a) If x = y or no relation can be established

b) If x > y

c) If x < y

d)

If x ≥ y

e) If x ≤ y

Answer: (d)

I. x2 + 7x – 5x – 35 =0

x (x + 7) – 5 (x + 7) =0

(x + 7) (x – 5) = 0

x = −7, 5

II. y2 + 7y + 8y + 56 = 0

y(y + 7) + 8(y + 7) = 0

(y + 7) (y + 8) = 0

y = − 8, −7

So, x ≥ y

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