SBI clerk prelims 22 Feb 2020 Questions and Answers Detailed Explanation
MOST IMPORTANT previous year question answers - 2 EXERCISES
The following question based on SBI clerk topic of previous year question answers
(a) 1 : 2
(b) 3 : 5
(c) 3 : 4
(d) 2 : 5
e) None of these
The correct answers to the above question in:
Answer: (b)
Let 10 years ago, ages of Ram and Rahim were x years and 3x years, respectively.
Then, present age of Ram = (x + 10)
and present age of Rahim = (3x + 10)
According to the question,
$\text"x+10+5"/\text"3x+10+5" = 2/3$
⇒ 3x + 45 = 6x + 30
⇒ 3x = 15
∴ x = 5
Hence, required ratio = $\text"5+10"/\text"3×5+10"$
= $15/25$
= 3 : 5
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Question : 1
Two trains of length 140m & 120m are running in same direction on parallel tracks with speeds 132 kmph & 80 kmph respectively. How much time will they take to cross each other?
a) 7.09 sec
b) 18 sec
c) 11.7 sec
d) 4.42 sec
e) Cannot be determined
Answer »Answer: (b)
Required time = $\text"140+120"/\text"(132−80)× 5/18"$
= $\text"260×18"/\text"52×5"$
= 18 sec
Question : 2
A person sold a book at 20% profit. If he had bought it at 10% less cost and sold for Rs 90 more then he would have gained 40% profit. Find cost price of book.
a) Rs 800
b) Rs 1600
c) Rs 1500
d) None of these
e) Rs 1200
Answer »Answer: (c)
let CP of book be Rs x
SP = Rs 1.2x
New CP = Rs 0.9x
New SP = Rs 1.2x + 90
ATQ, 0.9x × $140/100$ = 1.2x + 90
1.26x = 1.2x + 90
x = Rs 1500
Directions:
In each question two equations numbered (I) and (II) are given. You have to solve both the equations and mark appropriate answer.
Question : 3
I. x = $√{25}$ and II. y3 = 125
a) If x = y or no relation can be established
b) If x > y
c) If x < y
d) If x ≥ y
e) If x ≤ y
Answer »Answer: (a)
I. x = 5
II. y = 5
So, x=y
Question : 4
A car can cover a distance in 4 hour at speed 60 kmph then by what percent should the speed of car be increased to cover the same distance in 2.5 hr?
a) 60%
b) 40%
c) 50%
d) 100%
e) 75%
Answer »Answer: (a)
distance = 240 kms
Required speed = $240/2.5$ = 96 kmph
Required % = $\text"96−60"/60 × 100$ = 60%
Question : 5
12 men can do a work in 10 days while 10 women can do the same work in 18 days. In how many days 4 men & 6 women together can do the same work?
a) $120/7$ days
b) 24 days
c) $180/13$ days
d) 15 days
e) 18 days
Answer »Answer: (d)
let total work be 360 units
Efficiency of 1 man = $360/\text"12×10"$ = 3 units/day
Efficiency of 1 woman = $360/\text"10×18"$ = 2 units/day
Required time = $360/\text"4×3+6×2"$ = 15 days
Directions:
What will come in the place of question (?) mark in following number series:
Question : 6
72000, 36000, 12000, 3000, 600, ?
a) 120
b) 200
c) 30
d) 150
e) 100
Answer »Answer: (e)
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