SBI PO 2019 - Category wise Question and Answer Practice Test with Solutions & PDF

SBI PO PRACTICE TEST [1 - EXERCISES]

SBI PO 2019

Directions:

Study the following pie-chart and table carefully to answer the questions that follow.

Percentage of visitors (male and female) in a museum on the given 3 days-Friday, Saturday and Sunday is depicted in the pie chart given below.

Total number of visitors on the given three days = 400 Ratio of male visitors to female visitors on the given three days is depicted in the table given below:

Days Male : Female
Friday 2 : 3
Saturday 7 : 5
Sunday 5 : 4

[S.B.I.(PO)Prelims 2019]

Question : 91 [SBI-PO-2019]

The number of female visitors on Friday was what percentage of the number of female visitors on Sunday?

a) 70%

b) 85%

c) 80%

d) 65%

e) 75%

Answer: (e)

Day Male Female Total
Friday 40 60 100
Saturday 70 50 120
Sunday 100 80 180

 

Required percentage = (60/80) × 100 = 75%.

Question : 92 [SBI-PO-2019]

A started business with Rs. 600 and B with Rs. 900. After 5 months B left and C joined with capital Rs. 600 less than B. If at the end of year profit of C was Rs 3500, then find the total profit at the end of year.

a) Rs. 46000

b) Rs. 36000

c) Rs. 28000

d) Rs. 23000

e) None of these

Answer: (d)

Ratio of the equivalent capitals of A, B and C for 1 month = 600 × 12 : 900 × 5 : 300 × 7 = 24 : 15 : 7

According to question 7 ≡ Rs. 3500 ⇒ 1 ≡ Rs. 500

The total profit at the end of year = 24 + 15 + 7 = 46 ≡ 46 × Rs. 500 = Rs. 23000

Question : 93 [SBI-PO-2019]

Cost price of A is twice the cost price of B. If the selling price of B is Rs.3600 and it is sold at the profit of 20%, then find the cost price of A.

a) Rs. 3000

b) Rs. 6000

c) Rs. 8000

d) Rs. 2000

e) Rs. 10000

Answer: (b)

Given, selling price of B = 1.20 × cost price of B

⇒ Cost price of B = 3600 ÷ 1.20 = Rs.3000

According to question,

Cost Price of A = 2 × Cost price of B

Hence, the cost price of A = 2 × Rs.3000 = Rs.6000.

Question : 94 [SBI-PO-2019]

Train A crosses a vertical pole at the speed of 15 m/s in 20 seconds. Speed of train A is 3 m/s less than the speed of train B and length of train B is 30 meter less than length of train A. Find the time taken by Train B to cross 270 meter long platform.

a) 20 seconds

b) 15 seconds

c) 30 seconds

d) 45 seconds

e) 40 seconds

Answer: (c)

Let the length of Train A be L meters, then

According to question,

$L/15$= 20

⇒ L = 300 m

∴ Length of train A is 300 m

So, length of train B = 300 – 30 m = 270 meters

Speed of train B = 15 + 3 = 18 m/s

When B crosses a 270 m long platform,

Time = $\text"270 + 270"/18$ seconds = 30 seconds

Hence, the required time = 30 seconds.

Question : 95 [SBI-PO-2019]

The ratio of speed of a boat in still water to speed of the current is 10 : 1. If ratio of the time taken by the boat to travel D km downstream to the time taken to travel (D – 45) km upstream is 3 : 2. Find the value of D.

a) 88

b) 54

c) 110

d) 99

e) 66

Answer: (d)

Let ratio of speed of a boat in still water to speed of the current is 10x : x,

then

$\text"D / ( 10+1 ) x" /\text "D - 45/ ( 10 - 1) x"$=$3/2$

⇒ 18D = 33D – 33 × 45

⇒ 15D = 33 × 45

⇒ D = 99

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