SBI PO 2019 Questions and Answers Detailed Explanation
MOST IMPORTANT previous year question answers - 1 EXERCISES
The following question based on SBI PO topic of previous year question answers
(a) 88
(b) 54
(c) 110
(d) 99
e) 66
The correct answers to the above question in:
Answer: (d)
Let ratio of speed of a boat in still water to speed of the current is 10x : x,
then
$\text"D / ( 10+1 ) x" /\text "D - 45/ ( 10 - 1) x"$=$3/2$
⇒ 18D = 33D – 33 × 45
⇒ 15D = 33 × 45
⇒ D = 99
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Read more sbi po prelims 2019 Based Previous Year Questions and Answers
Question : 1
4 years hence the sum of ages of A and B will be 16 years more than the sum of the present ages of B and C. 4 years ago the sum of A’s age and C’s age was 32 years, then what is the present age of C?
a) 18 years
b) 14 years
c) 10 years
d) 16 years
e) 12 years
Answer »Answer: (d)
According to the question:
Present age of A and C:
A + C = 40 ............(i)
After 4 years, sum of ages of A and B will be 16 years more than the sum of the present ages of B and C.
A + 4 + B + 4 = B + C + 16
A - C = 8 ............(ii)
On solving eq(i) and eq(ii).
2A = 48
A = 24
Then, the present age of C:
24 + C = 40
C = 16 Years
Question : 2
40 men can complete a work in 48 days. If 64 men started working and after X days, 32 more men joined the work. If the remaining work is completed in 16$2/3$ days, then find the value of X.
a) 2
b) 5
c) 8
d) 4
e) 6
Answer »Answer: (b)
By MDW formula,
Total work = 48× 40 = 1920 units
Now,
1920 = 64 × X + (64 + 32) × (50/3)
⇒ 1920 = 64X + 1600
⇒ 64X = 320
⇒ X = 5
Question : 3
Cost of gardening the circular field C at Rs.10 per meter square is Rs.3465. Side of the square field S is equals to the diameter of the circular field C. find the perimeter of square field.
a) 108
b) 84 m
c) 78 m
d) 112 m
e) None of these
Answer »Answer: (b)
Let r meter be the radius of circular field C, then
Area of circular field C × 10 = 3465
⇒ πr 2 × 10 = 3465
⇒ r 2 = $441/4$
⇒ r = $21/2$ m
Side of square field S = 2 × r = 21m
Perimeter of square field = 4 × 21 = 84 meters
Question : 4
Train A crosses a vertical pole at the speed of 15 m/s in 20 seconds. Speed of train A is 3 m/s less than the speed of train B and length of train B is 30 meter less than length of train A. Find the time taken by Train B to cross 270 meter long platform.
a) 20 seconds
b) 15 seconds
c) 30 seconds
d) 45 seconds
e) 40 seconds
Answer »Answer: (c)
Let the length of Train A be L meters, then
According to question,
$L/15$= 20
⇒ L = 300 m
∴ Length of train A is 300 m
So, length of train B = 300 – 30 m = 270 meters
Speed of train B = 15 + 3 = 18 m/s
When B crosses a 270 m long platform,
Time = $\text"270 + 270"/18$ seconds = 30 seconds
Hence, the required time = 30 seconds.
Question : 5
Cost price of A is twice the cost price of B. If the selling price of B is Rs.3600 and it is sold at the profit of 20%, then find the cost price of A.
a) Rs. 3000
b) Rs. 6000
c) Rs. 8000
d) Rs. 2000
e) Rs. 10000
Answer »Answer: (b)
Given, selling price of B = 1.20 × cost price of B
⇒ Cost price of B = 3600 ÷ 1.20 = Rs.3000
According to question,
Cost Price of A = 2 × Cost price of B
Hence, the cost price of A = 2 × Rs.3000 = Rs.6000.
Question : 6
A started business with Rs. 600 and B with Rs. 900. After 5 months B left and C joined with capital Rs. 600 less than B. If at the end of year profit of C was Rs 3500, then find the total profit at the end of year.
a) Rs. 46000
b) Rs. 36000
c) Rs. 28000
d) Rs. 23000
e) None of these
Answer »Answer: (d)
Ratio of the equivalent capitals of A, B and C for 1 month = 600 × 12 : 900 × 5 : 300 × 7 = 24 : 15 : 7
According to question 7 ≡ Rs. 3500 ⇒ 1 ≡ Rs. 500
The total profit at the end of year = 24 + 15 + 7 = 46 ≡ 46 × Rs. 500 = Rs. 23000
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