time and work Model Questions & Answers, Practice Test for ssc mts tier 1 2024

Answer: (a)

According to the formula

${M_1D_1}/{W_{a1}} = {M_2D_2}/{W_{a2}}$

⇒${18 × 5}/{1440} = {m_2 × 8}/{1920}$

∴ $m_2 = {1920 × 18 × 5}/{8 × 1440}$ = 15

Answer: (b)

Efficiency is proportional to days

$X ↙100⟶↖(+60%)Y↙160$

⇒100 × 16 = 160 × D

∴ D = ${100 × 16}/{160}$ = 10 days

Answer: (d)

Net distance gained by car over the bus = 40 + 60 = 100m, in 20 sec.

Time = ${\text"Distance"}/{\text"Relative speed"}⇒ 20 = {100}/{(36 × 5/{18}) - S_2}$

⇒$S_2$ = 5 m/s = 18 kmph.

Answer: (c)

Let the man alone do the work in x days.

Then, the woman alone do the work in 2x days.

Their one day's work = $1/8$ th part of whole work

i.e. $1/x + 1/{2x} = 1/8$

⇒ x = 12 days

∴ man takes 12 days and woman 2x = 24 days.

Alternate Method :-

Let man can finish work in x days and is twice efficient than woman Man can finish the work in

${2x}/{2 + 1}$ = 8⇒x = 12days

woman finish the work in 2 × 2 = 24 days

Answer: (b)

5 Men can do work in 10 days, 1 man will do in 10 × 5. 12 women can do work in 15 days, 1 women will do in 12 × 15

ATQ. 5 men and 6 women will do in

⇒$5/{10 × 5} + 6/{12 × 15}$

⇒$1/{10} + 1/{30} = 4/{30}$

= $2/{15} i.e. {15}/2 or 7 {1/2}$ days