algebraic expressions Model Questions & Answers, Practice Test for ssc mts paper 1 2023
ssc mts paper 1 2023 SYLLABUS WISE SUBJECTS MCQs
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If the ages of P and R are added to twice the age of Q, the total becomes 59. If the ages of Q and R are added to thrice the age of P, the total becomes 68. And if the age of P is added to thrice the age of Q and thrice the age of R, the total becomes 108. What is the age of P?
Answer: (a)
P + R + 2Q = 59;
Q + R + 3P = 68
and P + 3(Q + R) = 108
Solving the above two equations, we get P = 12years.
The inequality $3n^2$ – 18n + 24 > 0 gets satisfied for which of the following values of n?
Answer: (c)
$3n^2$ – 18n + 24 = 0
or, $n^2$ – 6n + 8 = 0 or, (n – 4) (n – 2) = 0
∴ n = 4, 2
∴ n > 4
What would be the maximum value of Q in the following equation? 5P9 + 3R7 + 2Q8 = 1114
Answer: (b)
5P9 + 3R7 + 2Q8 = 1114
For the maximum value of Q, the values of P and R should be the minimum, i.e. zero each.
Now, 509 + 307 + 2Q8 = 1114
or, 816 + 2Q8 = 1114
or, 2Q8 = (1114 – 816 =) 298
So, the reqd value of Q is 9.
The difference between a two-digit number and the number obtained by interchanging the position of the digits of that number is 54. What is the sum of the digits of that number?
Answer: (a)
Let the two-digit no. be 10x + y.
According to question,
(10x + y) – (10y + x) = 54
9x – 9y = 54 x – y = 6
Assuming that A, B and C are different single-digit numerical values other than what is already used in following equation, what number C definitely cannot be ? 8A2 + 3B5 + C4 = 1271
Answer: (b)
Since, A + B + C = 16
(Possible values of A, B and C are 0, 6 & 9).
Also A # B, B # C, A # C.
If C = 6, A + B should be 10, which is not possible.
If C = 9, A + B should be 7, which is also not possible.
If C = 0, A + B should be 16, which is also not possible.
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