time and distance Model Questions & Answers, Practice Test for ssc chsl tier 1 2024
ssc chsl tier 1 2024 SYLLABUS WISE SUBJECTS MCQs
Number System
Simplification
Power, Indices And Surds
Time & Work
Time & Distance
Mensuration
In covering certain distance, the average speeds of X and Y are in the ratio 4 : 5. If X takes 45 minutes more than Y to reach the destination, then what is the time taken by Y to reach the destination?
Answer: (a)
Time taken by X and Y to covered distance is 5x and 4x respectively
∴ 5x – 4x = 45 min
x = 45 min
∴ Time = 4x = 45 × 4 = 180 min
Excluding stoppages, the speed of a bus is 54 km/hr and including stoppages, it is 45 km/hr, for how many minutes does the bus stop per hour?
Answer: (c)
Stoping per hour = ${54-45}/45×60$
= $9/45×60=12$ min
A motor boat, whose speed is 15 km/ hour in still water goes 30 km down–stream and comes back in a total of 4 hour and 30 minutes. The speed of the stream is
Answer: (b)
Let the speed of stream be 'x' km/hour.
⇒${30}/{(15 + x)} + {30}/{(15 - x)}$ = 4.5
⇒${15 - x + 15 + x}/{(15 + x)(15 - x)} = {4.5}/{30}$
⇒${30}/{225 - x^2} = {45}/{300}$
⇒225 – $x^2$ = 200
⇒$x^2$ = 25
⇒x = 5
So, option (b) is correct
Two men P and Q start from a place walking at 5 km/h and 6.5 km/h, respectively. What is the time they will take to be 92 km apart, if they walk in opposite directions?
Answer: (d)
∵ Time = ${\text"Distance"}/{\text"Speed"} = {92}/{6.5 + 5} = {92}/{11.5}$= 8 h
By increasing the speed of his car by 15 km/hour, a person covers 300 km distance by taking an hour less than before. The original speed of the car was
Answer: (a)
Let the original speed of car be = x km/hour
${300}/x - {300}/{(x + 15)}$ = 1
⇒${x + 15 - x}/{(x + 15)x} = 1/{300}$
⇒$x^2$ + 15x – 4500 = 0
⇒(x + 75)(x – 60) = 0
⇒x ≠ – 75
x = 60
So, option (c)is correct.
ssc chsl tier 1 2024 IMPORTANT QUESTION AND ANSWERS
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