simplification Model Questions & Answers, Practice Test for ssc chsl tier 1 2024

Answer: (a)

?=$36/7×49/6×8/63$

= $16/3=5{1/3}$

Answer: (b)

Given, x = (b – c) (a – d), y = (c – a) (b – d)

and z = (a – b) (c – d)

∴ x + y + z = (b – c) (a – d) + (c – a) (b – d) + (a – b) (c – d) = 0

∴ $x^3 + y^3 + z^3$ = 3xyz

Answer: (b)

∴ required number = 91 × 91 – 8115 = 166

Answer: (a)

${16}/{23} = 1/{{23}/{16}} = 1/{1 + 7/{16}} = 1/{1 + (1/{{16}/7})} = 1/{1 + 1/{2 + (2/7)}}$

= $1/{1 + [1/{2 + (1/{7/2})}]} = 1/{1 + [1/{2 + {1/{3 + 1/2}}}]}$

On comparing equations we get a = 1, b = 2 and c = 3

Mean = a + b + c/3 = 6/3 = 2

Answer: (c)