number system Model Questions & Answers, Practice Test for ssc chsl tier 1 2024

Answer: (d)

Let the numbers be $x$ and $(x + 1),$

∴ $x(x + 1)$ = 8556

or, $x^2 + x – 8556 = 0$

or, $x^2 + 93x – 92 x – 8556 = 0$

or, $(x^2 + 93) (x – 92) = 0$

∴ $x$ = 92

Alternate Method

Out of the given alternatives

92 × 93 = 8556

Answer: (c)

Required number of bananas

= $21/7 × 54 = 162$ dozen

Answer: (d)

Given a = 6b = 12c = 27d = 36e

Multiplied and Divide by 108 in whole expression

${108a}/108 = {108b}/18 = {108c}/9 ={108d}/4 = {108e}/3$

$1/108a = 1/18b = 1/9c = 1/4d = 1/3e = k$ (say)

⇒ a = 108k, b = 18k, c = 9k, d = 4k, e = 3k

So it is clear that $(a/6, c/d)$ contains a number $c/d = (9/4)$

which is not an integer

Answer: (a)

Quotient = 143K + 28

Now, when same number is divided by 13.

So, we check 143 is divided by 13 or not.

Here, 143 is completely divided by 13.

Hence we divides 28 by 13 then remainder is 2.

Answer: (c)

Putting the value of x = – 0.5 in all the options.

(a) $2^{1/-0.5} = 2^{-2} = 1/4$

(b) $1/(-0.5)^2 = 4$

(c) $1/{-0.5} = -2$

(d) $2^{-0.5} = 1/√2$

So, clearly (c) is smallest.