algebraic expressions Model Questions & Answers, Practice Test for ssc cgl tier 1 2023
ssc cgl tier 1 2023 SYLLABUS WISE SUBJECTS MCQs
Number System
Ratio Proportion & Partnership
Averages
Percentages
Profit & Loss
Time & Work
Time & Distance
Simple Interest & Compound Interest
Mensuration: Area & Volumes
Algebraic Expressions
Linear Equations
Squareroots & Cuberoots
Directions :
In each of the following questions two equations are given. You have to solve them and Give answer
- if p < q
- if p > q
- if p ≤ q
- if p ≥ q
- if p = q
I. $p^2$ – 7p = – 12
II. $q^2$ – 3q + 2 = 0
Answer: (e)
I. $p^2$ – 7p = – 12
or, $p^2$ – 7p + 12 = 0
or, (p – 3) (p – 4) = 0
or, p = 3 or 4
II. $q^2$ – 3q + 2 = 0
or, (q – 2) (q – 1) = 0
or, q = 1 or 2
Hence, p > q
Directions :
For the two given equations I and II give answer
- if p is greater than q
- if p is smaller than q
- if p is equal to q
- if p is either equal to or greater than q
- if p is either equal to or smaller than q.
I.$3p^2$ +2p –1 = 0
II. $2q^2$ + 7q +6 =0
Answer: (c)
I. $3p^2$ +2p – 1 = 0
or, $3p^2$ + 3p – p – 1 = 0
or, 3p(p + l) – 1(p + 1) = 0
or, (3p – l)(p + 1) = 0
Therefore, p = $1/3,-1$
II. $2q^2$ + 7q + 6 = 0
or, $2q^2$ + 4q + 3q + 6 = 0
or, 2q(q + 2) + 3(q + 2) = 0
or, (2q + 3)(q + 2) = 0
Therefore, q = ${-3}/2,-2$ Thus p > q
Directions :
In each question below one or more equation(s) is/are provided. On the basis of these, you have to find out relation between p and q.
- if p = q
- if p > q
- if q > p
- if p ≥ q
- if p ≥ q
I. $4q^2$ + 8q = 4q + 8
II. $p^2$ + 9p = 2p – 12
Answer: (d)
I. $4q^2$ + 8q = 4q + 8
or, $q^2$ + q – 2 = 0
or, (q – 1) (q + 2) = 0
∴q = 1 or – 2
II. $p^2$ + 9p = 2p – 12
or, $p^2$ + 7p + 12 = 0
or, (p + p) (p + (c) = 0
∴ p = – 3 or – 4
Hence, q > p
Directions :
For the two given equations I and II give answer
- if p is greater than q
- if p is smaller than q
- if p is equal to q
- if p is either equal to or greater than q
- if p is either equal to or smaller than q.
I. $p^2$ + 13p + 42 =0
II. $q^2$ = 36
Answer: (b)
I. $p^2$ + 13p + 42 = 0
or, $p^2$ + 7p + 6p + 42 = 0
or, p(p+7) + 6(p + 7) = 0
or, (p+6)(p+7) = 0
or, p = – 6,–7
II. $q^2$ = 36
q = $√{36}$
∴q = +6, –6
Therefore, p ≤ q.
Directions :
In each of the following questions two equations are given. You have to solve them and Give answer
- if p < q
- if p > q
- if p ≤ q
- if p ≥ q
- if p = q
I. $p^2$ – 8p + 15 = 0
II. $q^2$ – 5q = – 6
Answer: (a)
I. $p^2$ – 8p + 15 = 0
or, (p – 3) (p – 5) = 0
or, p = 3 or 5
II. $q^2$ – 5q + 6 = 0
or, (q – 2) (q – 3) = 0
or, q = 2 or 3
Hence, p ≥ q
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