surds and indices Model Questions & Answers, Practice Test for ibps po prelims 2023
ibps po prelims 2023 SYLLABUS WISE SUBJECTS MCQs
Number System
Simplification
Surds & Indices
Ratio & Proportion
Profit & Loss
Time & Work
Simple Interest & Compound Interest
Mensuration: Area & Volumes
If $[[{(1/7^2)^{-2}}]^{-1/3}]^{1/4}$ = $7^m$, then find the value of m
Answer: (c)
$[[(1/7^2)^{-2}]^{-1/3}]^{1/4}=7^m$
$⇒[[(7^{-2})^{-2}]^{-1/3}]^{1/4}=7^m$
$⇒[(7^4)^{-1/3}]^{1/4}=7^m$
$⇒(7^{-4/3})^{1/4}=7^m$
$⇒7^{-1/3}=7^m$
$∴m=-1/3$
${16 × 32}/{9 × 27 × 81}$ = ?
Answer: (d)
? = ${16 × 32}/{9 × 27 × 81} = {2^4 × 2^5}/{3^2 × 3^3 × 3^4} = {(2)^{4+5}}/{(3)^{2+3+4}} = (2/3)^9$
Simplify : $ 13^{1/5}.17^{1/5}$
Answer: (c)
$13^{1/5}.17^{1/5}=(13×17)^{1/5}=221^{1/5}=^5√{221}$
On simplification $[{x^{a/{a-b}}/x^{a/{a+b}}÷{x^{b/{b-a}}/x^{b/{b+1}}]]^[a+b]$ reduces to
Answer: (b)
$(√9)^3 × (√81)^5 ÷ (27)^2 = (3)^{(?)}$
Answer: (c)
$(√9)^3 × (√81)^5 ÷ (27)^3 = (3)^{(?)}$
$(3)^3 × (9)^5 ÷ (3)^{3 × 2} = (3)^{?}$ or $(3)^3 × (3)^{2 × 5} ÷ (3)^6 = (3)^{?}$
$(3)^{3 + 10 – 6} = (3)^{?}$ or $(3)^7 = (3)^{?}$
? = 7
ibps po prelims 2023 IMPORTANT QUESTION AND ANSWERS
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Profit and Loss Questions Test For IBPS PO Prelims 2023 »
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Surds and Indices Problems and Solutions For IBPS PO 2023 »
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