mensuration area volumes Model Questions & Answers, Practice Test for ibps po prelims 2023

Answer: (a)

Area of the square = $(4)^2 = 16 cm^2$

Area of circle of the center

4 × $π/4 (2/2)^2 = π cm^2$

Total area removed = π + π = 2π $cm^2$

2 × ${22}/7 = {44}/7 cm^2$

∴ Area of shaded region

= 16 - ${44}/7 = 9 5/7 cm^2$

Answer: (b)

According to question

$4πr^2 = 6a^2$

$r^2/a^2 = 6/{4π}$

Ratio of their volume = ${4/3 π r^3}/{a^3}$

= $4/3 π (r/a)^3 = {4π}/3 . 6/{4π} √{6/{4π}} = √{6/π}$

Square of their volume ratio = $6/π$ = 6 : π

Answer: (b)

Statement I

Let side BC = x cm.

Given Area of ΔBFC = 6 $cm^2$

$1/2$ × 3 × x = 6 ⇒ x = 4 cm

In ΔBFC, $BF^2 = x^2 + 9 = 16 + 9 ⇒ BF^2$ = 25

∴ BF = 5

∴ area of rectangle ABCD, $pq^2 = p (2)^2 cm^2$

Statement II

which is of the form $pq^2$ .

While the area of EBFD cannot be the form of $r^2 cm^2$ .

Answer: (b)

As, 1 m = 1000 mm

∴ 10 m = 10000 mm

Number of 200 mm lengths that can be out from 10 m of ribbon

= ${10000}/{200}$ = 50

Answer: (a)

S = $x/y + y/z + z/x$

Area = $√{S(S– a)(S– b)(S– c)}$

= $√{(x/y + y/z + z/x)(x/y)(y/z)(z/x)}$

= $√{x/y + y/z + z/x}$